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Oxana [17]
4 years ago
8

(01.01 MC) Which of the following could be considered a scientific statement

Chemistry
1 answer:
Mashcka [7]4 years ago
7 0

Answer:

hmmmm not sure and don't know

Explanation:

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A student standardizes a solution of aqueous NaOH against a measured mass of solid potassium hydrogen phthalate. She then uses t
wlad13 [49]

Answer:

(D) Neither I nor II

Explanation:

The reagent potassium hydrogen phthalate is found in pure form and it is not partially hydrated .

The pallet form of NaOH ( solid form )  absorbs carbon dioxide gas from the atmosphere but NaOH in solution form does not absorb carbon dioxide .

Hence option D ) is right choice .

8 0
4 years ago
Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002
marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The pK_a=4.756

The value of the dissociation constant = K_a

pK_a=-\log[K_a]

K_a=10^{-4.756}=1.754\times 10^{-5}

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

HAc\rightleftharpoons H^++Ac^-

Initially

c

At equilibrium ;

(c-cα)                                cα        cα

The expression of dissociation constant is given as:

K_a=\frac{[H^+][Ac^-]}{[HAc]}

1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}

1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}

1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M

The pH of the solution ;

pH=-\log[H^+]

=-\log[0.0001901 M]=3.72

3 0
4 years ago
Helllllllpppppppppppp<br><br>l​
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Explanation:

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True or False? Changes in temperature, pressure and volume affect the behavior of gases more than they affect solids and liquids
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True

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ElenaW [278]

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<h2>A.EXACTLY CROSSING EARTH'S ORBIT OF THE SUN</h2>
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