Which alkane may be obtained by the reduction of 2-bromo propane

Chemistry

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

To reduce a haloalkane, it has to be eliminated first. This is because 2 bromopropanes are a saturated compound that can not be reduced by a saturated compound. Dehydrohalogenation of the haloalkanes into the form of propene and hydrogen bromide can lead to the elimination. The propene is then reduced to propane.

S_A_V [24]3 years ago

4 0

Answer:

Propane

Step-by-step explanation:

One way to reduce an alkyl halide is the Grignard reaction.

You react 2-bromopropane with magnesium in dry ether to form isopropylmagnesium bromide.

In the second step, the strongly basic Grignard reagent abstracts a proton from water and is converted to propane.

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2 years ago

What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

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a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

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See figure 1

I hope it helps!