Answer:
See explanation
Explanation:
A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions(Khan Academy).
From the species shown in the image we can write the molecular equation, ionic equation and net ionic equation and also identify the spectator ions.
Chemical equation: KX + BY --------> BX + AY
Ionic Equation; X^- + A^+ + B^+ + Y^- -----> BX + A^+ + Y^-
Spectator ions; A^+ and Y^-
Net Ionic Equation; X^- + B^+ ------> BX
The image of the bonds are missing, so i have attached it.
Answer:
A) - Sigma bond
-Sp³ and Sp³
- None
B) - Sigma and pi bond
- Sp² of C and p of O
- p of C and P of O
Explanation:
A) For compound 1;
- the molecular orbital type is sigma bond due to the end-to-end overlapping.
- Atomic orbitals in the sigma bond will be Sp³ and Sp³
- Atomic orbitals in the pi bond would be nil because there is no pi bond.
B) For compound 2;
- the molecular orbital type is sigma and pi bond
-Atomic orbitals in the sigma bond would be Sp² of C and p of O
- The Atomic orbitals in the pi bond will be; p of C and p of O
Answer:
When you heat ice, the individual molecules gain kinetic energy, but until the temperature reaches the melting point, they don't have energy to break the bonds that hold them in a crystal structure. They vibrate more quickly within their confines as you add heat, and the temperature of the ice goes up.
Answer:
The amount of heat required to vaporize 2.58 kg of water at its boiling point is 5,830.8 kJ.
Explanation:
A substance undergoes a change in temperature when it absorbs or gives up heat to the environment around it. However, when a substance changes phase it absorbs or gives up heat without causing a change in temperature. The heat Q that is necessary for a mass m of a certain substance to change phase is equal to:
Q = m*L
where L is called the latent heat of the substance.
In this case:
- m=2.58 kg
- The heat of vaporization of water is L=2260*10³ J/kg
Replacing:
Q= 2.58 kg* 2260*10³ J/kg
Q= 5,830,800 J = 5,830.8 kJ (Being 1,000 J= 1 kJ)
<u><em>The amount of heat required to vaporize 2.58 kg of water at its boiling point is 5,830.8 kJ.</em></u>
I would say try the first answer
