All categories

3 years ago

Pls help me ASAP its very urgent

Chemistry

1 answer:

vovikov84 [41]3 years ago

8 0

Answer:

C Region

Explanation:

C Region contains all the liquids as 0 °C is the freezing point of water (Crystals of water are formed leaving it no more in the liquid state) and 100 °C is the boiling point (The water boils leaving it no more in the liquid state).

Hence, All liquids are contained in the C region.

$\rule[225]{225}{2}$

Hope this helped!

You might be interested in

Consider the reaction 2 NO + O2 → 2 NO2

Sonbull [250]

Answer:

(a) Rate at which $NO_2$ is formed is 0.050 M/s

(b) Rate at which $O_2$ is consumed is 0.0250 M/s.

Explanation:

The given reaction is:-

$2NO+O_2\rightarrow 2NO_2$

The expression for rate can be written as:-

$-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}$

Given that:- $\frac{d[NO]}{dt}=-0.050\ M/s$ (Negative sign shows consumption)

$-\frac{1}{2}\frac{d[NO]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}$

$-\frac{d[NO]}{dt}=\frac{d[NO_2]}{dt}$

$-(-0.050\ M/s)=\frac{d[NO_2]}{dt}$

$\frac{d[NO_2]}{dt}=0.050\ M/s$

(a) Rate at which $NO_2$ is formed is 0.050 M/s

$-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}$

$-\frac{1}{2}\times -0.050\ M/s=-\frac{d[O_2]}{dt}$

$\frac{d[O_2]}{dt}=0.0250\ M/s$

(b) Rate at which $O_2$ is consumed is 0.0250 M/s.

5 0

3 years ago

Explain the energy flowing as you hold an ice cream cone. (Be sure to mention "the system," "the surroundings," and how energy i

Serggg [28]

Answer:

This is what I put, it hasn't been graded though...

Within the system, the energy is flowing from your hand to the ice cream cone. Energy is also flowing from the surroundings to the ice cream cone unless it's reeeeaally cold in the surroundings in which case why are you even holding an ice cream cone when it's that cold?

4 0

3 years ago

Pleeease answer! 10 POINTS

Korvikt [17]

It is false because an endothermic reaction will also start when energy is received from the environment when there is no solution involved

6 0

3 years ago

Calculate the molarity of the solution.

IRISSAK [1]

<span>The formula given for it is
moles = given wt/mol.Wt

Mol.wt of nacl
nacl=23+35.5
=58.5 gm
Moles = 29/58.5
= 0.495
~ 0.15 moles </span>

8 0

3 years ago