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3 years ago

Does gravity always include the Earth’s pull or can it be between other objects?

2 answers:

7 0

Well other planets have a gravitational pull that's what keep the planet's orbiting the sun. But the amount of gravity differs by mass.

Hope this helps :)

sammy [17]3 years ago

4 0

What a great question !

There is a pair of forces of gravity (one in each direction) between EVERY two specks of mass in all of creation.

-- Between you and the Earth.

-- Between the Moon and the Earth.

-- Between the Moon and you.

-- Between you and your dog.

-- Between your dog and your goldfish.

-- Between every pair of corn flakes in your cereal bowl.

-- Between the lint in your pocket and every grain of sand on the beach on the far side of the farthest planet in orbit around the farthest star in the farthest galaxy on the other side of the Universe. You don't feel it, and it's too small to measure, but its strength can be calculated.

You might be interested in

A 3-kg skateboard is rolling down the sidewalk at 4 m/s when it collides with a 1-kg skateboard that was initially at rest. If t

irga5000 [103]

Answer:

2 m/s

Explanation:

Parameters given:

Mass of first skateboard, m = 3 kg

Initial speed of first skateboard, u = 4 m/s

Mass of second skateboard, M = 1 kg

Initial speed of second skateboard, U = 0 m/s

Final speed of second skateboard, V = 6 m/s

Using the principle of the conservaton of momentum, the total initial momentum is equal to the total final momentum.

Momentum is the product of mass and velocity. This implies that:

m*u + M*U = m*v + M*V

(3*4) + (1*0) = (3*v) + (1*6)

12 + 0 = 3v + 6

=> 3v = 12 - 6

3v = 6

v = 6/3 = 2 m/s

The final speed of the 3 kg skateboard is 2 m/s

8 0

4 years ago

Read 2 more answers

Which of the following illustrates an increase in potential energy? Group of answer choices a wind-up toy winding down a person

horrorfan [7]

Answer:

A person climbs a set of stairs

Explanation:

Potential energy is said to be possessed by an object due to its position. As the height from the ground level increase, the potential energy increases. It is calculated by the below formula as :

P = mgh

Out of the given options, the option that illustrates an increase in potential energy is option (b) i.e. a person climbs a set of stairs. As he steps one stair, its position from ground increases. It means its potential energy increases.

7 0

3 years ago

The half-life of a certain isotope is 12 years. How much of a 600 g sample will remain after 36 years?

miskamm [114]

36/12= 3 3 IS THE AMOUT OF HALFLIVES

ONE HALF LIFE = 300

TWO HALF LIFE = 150

THREE HALF LIFE = 75

*Divide 600 three times

8 0

4 years ago

Blake has a mass of 72kg and Denise has a mass of 53kg. Blake and Denise are standing 2 meters apart on the dance floor. Denise

ivann1987 [24]

Answer:

6.36*10^-8 N

Explanation:

The magnitude of gravitational force of attraction is usually given by the formula

F = Gm1m2/r², where

F = magnitude of the force required

G = gravitational constant, 6.67*10^-11 m3 kg^-1 s^-2

m1 = mass of the first body, 72 kg

m2 = mass of the second body, 53 kg

r = radius between the bodies themselves, 2 m

Now, when we apply the formula directly, we get

F = (6.67*10^-11 * 72 * 53) / 2²

F = (6.67*10^-11 * 3816) / 4

F = 2.55*10^-7 / 4

F = 6.36*10^-8 N

8 0

3 years ago

We consider a projectile motion against a linear drag force D = −b∗v, where v is the velocity

Alex

Explanation:

(A) Sum of forces on the projectile in the y direction:

-bv − mg = ma

Acceleration is the derivative of velocity with respect to time:

-bv − mg = m dv/dt

Separate the variables:

bv + mg = -m dv/dt

-1/m dt = 1/(bv + mg) dv

-b/m dt = b/(bv + mg) dv

Integrate:

-b/m t |₀ᵗ = ln(bv + mg) |₀ᵛ

-b/m (t − 0) = ln(bv + mg) − ln(0 + mg)

-b/m t = ln(bv + mg) − ln(mg)

-b/m t = ln((bv + mg) / mg)

e^(-b/m t) = (bv + mg) / mg

bv + mg = mg e^(-b/m t)

bv = -mg + mg e^(-b/m t)

v = -mg/b (1 − e^(-b/m t))

Velocity is derivative of position with respect to time:

dz/dt = -mg/b (1 − e^(-b/m t))

Separate the variables:

-b/(mg) dz = (1 − e^(-b/m t)) dt

Integrate:

-b/(mg) z |ᵧᶻ = (t + m/b e^(-b/m t)) |₀ᵗ

-b/(mg) (z − h) = (t + m/b e^(-b/m t)) − (0 + m/b e^(0))

-b/(mg) (z − h) = t + m/b e^(-b/m t) − m/b

z − h = -mg/b (t + m/b e^(-b/m t) − m/b)

z = h − mg/b (t + m/b e^(-b/m t) − m/b)

(B) Repeat steps from part A, but this time in the x direction.

-bv = ma

-bv = m dv/dt

-b/m dt = 1/v dv

-b/m t |₀ᵗ = ln v |ᵥᵛ

-b/m (t − 0) = ln vₓ − ln v₀ₓ

-b/m t = ln (vₓ / v₀ₓ)

vₓ / v₀ₓ = e^(-b/m t)

vₓ = v₀ₓ e^(-b/m t)

dx/dt = v₀ₓ e^(-b/m t)

dx = v₀ₓ e^(-b/m t) dt

x |₀ˣ = -m/b v₀ₓ e^(-b/m t) |₀ᵗ

x − 0 = -m/b v₀ₓ e^(-b/m t) − (-m/b v₀ₓ e^(0))

x = -m/b v₀ₓ e^(-b/m t) + m/b v₀ₓ

x = m/b v₀ₓ (1 − e^(-b/m t))

To find z(x), find t in terms of x then substitute into z(t).

b x / (m v₀ₓ) = 1 − e^(-b/m t)

e^(-b/m t) = 1 − b x / (m v₀ₓ)

-b/m t = ln(1 − b x / (m v₀ₓ))

t = -m/b ln(1 − b x / (m v₀ₓ))

z = h − mg/b (-m/b ln(1 − b x / (m v₀ₓ)) + m/b (1 − b x / (m v₀ₓ)) − m/b)

z = h − mg/b (-m/b ln(1 − b x / (m v₀ₓ)) + m/b − x / v₀ₓ − m/b)

z = h − mg/b (-m/b ln(1 − b x / (m v₀ₓ)) − x / v₀ₓ)

The range is when z = 0:

0 = h − mg/b (-m/b ln(1 − b x / (m v₀ₓ)) − x / v₀ₓ)

h = mg/b (-m/b ln(1 − b x / (m v₀ₓ)) − x / v₀ₓ)

bh/(mg) = -m/b ln(1 − b x / (m v₀ₓ)) − x / v₀ₓ

-(b/m)² h/g = ln(1 − (b/m) x / v₀ₓ) + (b/m) x / v₀ₓ

Unfortunately, this can't be simplified further without using something called the Lambert W function.

x = v₀ₓ √(2h/g)

6 0

3 years ago