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alex41 [277]
3 years ago
13

Does gravity always include the Earth’s pull or can it be between other objects?

Physics
2 answers:
padilas [110]3 years ago
7 0

Well other planets have a gravitational pull that's what keep the planet's orbiting the sun. But the amount of gravity differs by mass.

Hope this helps :)

sammy [17]3 years ago
4 0

What a great question !

There is a pair of forces of gravity (one in each direction) between EVERY two specks of mass in all of creation.  

-- Between you and the Earth.

-- Between the Moon and the Earth.

-- Between the Moon and you.

-- Between you and your dog.

-- Between your dog and your goldfish.

-- Between every pair of corn flakes in your cereal bowl.

-- Between the lint in your pocket and every grain of sand on the beach on the far side of the farthest planet in orbit around the farthest star in the farthest galaxy on the other side of the Universe.  You don't feel it, and it's too small to measure, but its strength can be calculated.

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A copper telephone wire has essentially
Lunna [17]

Answer:

128.21 m

Explanation:

The following data were obtained from the question:

Initial temperature (θ₁) = 4 °C

Final temperature (θ₂) = 43 °C

Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

12820.51 cm = 12820.51 cm × 1 m / 100 cm

12820.51 cm = 128.21 m

Thus, the original length of the wire is 128.21 m

5 0
3 years ago
A 0.50 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frict
Genrish500 [490]

Explanation:

We have,

Mass of an object is 0.5 kg

Force constant of the spring is 157 N/m

The object is released from rest when the spring is compressed 0.19 m.

(A) The force acting on the object is given by :

F = kx

F=157\times 0.19\\\\F=29.83\ N

(B) The force is simply given by :

F = ma

a is acceleration at that instant

a=\dfrac{F}{m}\\\\a=\dfrac{29.83}{0.5}\\\\a=59.66\ m/s^2

6 0
3 years ago
WILL GIVE BRAINLIEST AND 30 POINTS!
frez [133]

Answer:

The answer is 16 and 24

Explanation:

8 0
3 years ago
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Which of the following statements best describes how waves interact with the media in which they move?
Leni [432]

Answer:

d

Explanation:

7 0
3 years ago
What effect would this have on the momentum?
Mariana [72]
Momentum describes an object in motion and is determined by the product of two variables: mass and velocity. Mass -- the weight of an object -- is usually measured in kilograms or grams for momentum problems. Velocity is the measure of distance traveled over time and is normally reported in meters per second. Examining the possible changes in these two variables identifies the different effects momentum can have on an object in motion.
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3 years ago
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