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katrin2010 [14]
3 years ago
13

A what is any small object that orbits a larger object​

Physics
1 answer:
erica [24]3 years ago
3 0

I think the the answer is satellite, I could be wrong

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A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a
gogolik [260]

Answer:

W= 638.1 J

Explanation:

As we know that

Work done is the area of the force and displacement diagram.

W=∫F.dx

W=Work

F=force

dx=Elemental displacement

From the diagram ,area A

A= 60 x 7.09 + 1/2 x 60 x 7.09

A= 638.1 J

So the work W

W= 638.1 J

3 0
3 years ago
PLS HEEEEEELPPPPPPPPP!!!!!!!!​
Sveta_85 [38]

txt now you need to add to 14 to those two to get it between the 14 and 19 and basically you will just be able to do this the liquid is 45 as you know that's all I got to say for you is that you have to answer the phone for you equational to pay

7 0
3 years ago
A screen is placed a distance dd to the right of an object. A converging lens with focal length ff is placed between the object
Elina [12.6K]

Answer:

2f

Explanation:

The formula for the object - image relationship of thin lens is given as;

1/s + 1/s' = 1/f

Where;

s is object distance from lens

s' is the image distance from the lens

f is the focal length of the lens

Total distance of the object and image from the lens is given as;

d = s + s'

We earlier said that; 1/s + 1/s' = 1/f

Making s' the subject, we have;

s' = sf/(s - f)

Since d = s + s'

Thus;

d = s + (sf/(s - f))

Expanding this, we have;

d = s²/(s - f)

The derivative of this with respect to d gives;

d(d(s))/ds = (2s/(s - f)) - s²/(s - f)²

Equating to zero, we have;

(2s/(s - f)) - s²/(s - f)² = 0

(2s/(s - f)) = s²/(s - f)²

Thus;

2s = s²/(s - f)

s² = 2s(s - f)

s² = 2s² - 2sf

2s² - s² = 2sf

s² = 2sf

s = 2f

8 0
3 years ago
jet is flying at 500 mph east relative to the ground. A Cessna is flying at 150 mph 60° north of west relative to the ground. Wh
Greeley [361]

Answer:

C. 590 mph

\vert v_{cj}\vert=589.49\ mph

Explanation:

Given:

  • velocity of jet, v_j=500\ mph
  • direction of velocity of jet, east relative to the ground
  • velocity of Cessna, v_c=150\ mph
  • direction of velocity of Cessna, 60° north of west

Taking the x-axis alignment towards east and hence we have the velocity vector of the jet as reference.

Refer the attached schematic.

So,

\vec v_j=500\ \hat i\ mph

&

\vec v_c=150\times (\cos120\ \hat i+\sin120\ \hat j)

\vec v_c=-75\ \hat i+75\sqrt{3}\ \hat j\ mph

Now the vector of relative velocity of Cessna with respect to jet:

\vec v_{cj}=\vec v_j-\vec v_c

\vec v_{cj}=500\ \hat i-(-75\ \hat i+75\sqrt{3}\ \hat j )

\vec v_{cj}=575\ \hat i-75\sqrt{3}\ \hat j\ mph

Now the magnitude of this velocity:

\vert v_{cj}\vert=\sqrt{(575)^2+(75\sqrt{3} )^2}

\vert v_{cj}\vert=589.49\ mph is the relative velocity of Cessna with respect to the jet.

8 0
3 years ago
How do P-Waves and S-Waves form?
marissa [1.9K]
P waves<span> are produced by all earthquakes. They are compression </span>waves<span> that </span>form <span>when rocks break due to pressure in the Earth. S </span>waves<span> are secondary </span>waves<span> that are also created during an earthquake. They travel at a slower speed than the </span>p-waves<span>.

S waves are the waves that come after the earthquake and P waves


</span>
6 0
3 years ago
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