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Nadya [2.5K]
3 years ago
7

What is the increase of entropy principle?

Engineering
1 answer:
Sonja [21]3 years ago
5 0

Answer:

Explanation:

For an isolated system (one that does not exchange matter of energy with its surroundings) entropy tends to raise.

The entire universe might be considered as an isolated system, and thus the entropy of the universe tends to rise and it never lowers.

Note that this is for isolated systems, not any systems.

A certain system might have its entropy go down, but for that it must exchange energy with its surroundings, and the entropy of the surroundings will raise. The change of entropy of the surroundings plus the change of entropy of the system (remember their signs) will always be positive.

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Oksanka [162]

Answer: making sure that they are up to date

Explanation:

7 0
3 years ago
If an object is near the surface of the earth the variation of its weight with distance from the center of the earth can ofteb b
zalisa [80]

Answer:

h=32.1 km

Explanation:

<em>solution:</em>

using newton law of gravitational attraction and newton second law:

W=\frac{Gmm_{E} }{r^{2} } \\a=\frac{Gm_{E}}{r^{2}} \\W=ma\\

m_{E}= mass of earth

r= distance between two masses

at sea level

a=g

r=R_{E}

a=\frac{Gm_{E}}{r^{2}}.............................(1)

Gm_{E} =gR_{E}^2.........................(2)

by substituting (2) and (1) a=g\frac{R_{E}^2 }{r^{2} } acceleration due to gravity at a distance r from the centre of the earth in terms of g (sea level)

so the weight of the object at a distance r from the centre of the earth (W=ma)

W=mg(Re^2/r^2)..........(3)

h the height above the surface of the earth: r=Re+h

putting the value of r in eq (3)

W=mg(Re/Re+h)^2

W=0.99 mg

solving for height h:

h=Re(1/√0.99)-(1))

h=32.1 km

4 0
3 years ago
A 4-lb ball B is traveling around in a circle of radius r1 = 3 ft with a speed (vB)1 = 6 ft&gt;s. If the attached cord is pulled
Salsk061 [2.6K]

Answer:

r₂ = 1.5 ft

t = 0.75 s

Explanation:

W = 4 lb    ⇒  m = W/g = 4 lb / 32.2 ft/s² = 0.12 slug

v₁ = 6 ft/s

r₁ = 3 ft

v₂ = 12 ft/s

r₂ = ?

t = ?

vr = 2 ft/s

Conserving angular momentum we have:

m*v₁*r₁ = m*v₂*r₂    ⇒     r₂ = v₁*r₁ / v₂

⇒     r₂ = (6 ft/s*3 ft) / (12 ft/s) = 1.5 ft

Now, we get the time as follows:

vr = <em>d</em> / t    ⇒   t = <em>d</em> / vr

where <em>d</em> is

<em>d</em> = Δr = r₁ - r₂ = 3 ft - 1.5 ft = 1.5 ft

finally

t = 1.5 ft / 2 ft/s

⇒ t = 0.75 s

5 0
3 years ago
What are the steps to execute an instruction by cpu?What is the function of DMA controller.
JulijaS [17]

Explanation:

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7. The CPU executes the instruction within the instruction register.

8. Go to step 3

Steps 3, 4, and 5 are called an instruction fetch. Notice that steps 3 – 8 constitute a cycle, the instruction execution cycle. It is shown graphically below.

A DMA controller can generate memory addresses and initiate memory read or write cycles. It contains several hardware registers that can be written and read by the CPU. These include a memory address register, a byte count register, and one or more control registers.

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3 years ago
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mixas84 [53]

Answer: Gasoline cars are bad because

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3 years ago
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