Answer every question of this quiz

when a metal, such as lead, is oxidied (loses electrons) to form a positive ion (cation), how does he solubility change?

o-na [289]

Answer: The size of the ion and the charge of the ion are the factors that affect solubility in water.

Explanation:

Lead lose electrons to become cations. Compounds with small ions tend to be less soluble than compounds with large ions. Large ions have higher solubility. This is because small ions are closely packed so it is difficult for water to break them apart.

Compounds with small ions seemingly have less solubility than those with large ions. The ions in the compound attract each other, and the water molecules attract the ions. Compounds would be soluble in water If the water molecules have a greater or higher attraction to the ions than ions have for each other.

8 0

4 years ago

A shaft 70 mm in diameter is being pushed at a speed of 400 mm/s through a bearing sleeve 70.2 mm in diameter and 250 mm long. T

Allushta [10]

Answer:

F=989.6 N

Explanation:

Given that

Diameter of shaft = 70 mm

Diameter of bearing sleeve =70.2 mm

So clearance h=0.1 mm

Speed V= 400 mm/s

Length of shaft = 250 mm

$\nu =0.005\ \frac{m^2}{s}\ , \rho=900\ \frac{kg}{m^3}$

We know that

$\mu =\rho\times\nu$

μ= 900 x 0.005 Pa-s

μ= 4.5 Pa-s

As we know that

From Newton's law of viscosity ,the shear stress given as follows

$\tau =\mu \dfrac{dU}{dy}$

We also know that

Force = shear stress x area

Now by putting the values

$\tau =4.5\times \dfrac{400}{0.1}$

$\tau=18,000 Pa$

So force

F= 18,000 x π x 0.07 x 0.25

F=988.6 N

6 0

3 years ago

How do you connect the pipe to the shower

vlada-n [284]

Answer:

you attach one side to the other

Explanation:

common sense

7 0

3 years ago

A force of 50N acts on a roller of mass 15 kg initially at rest on a frictionless surface. The roller travels 12 m while the for

kenny6666 [7]

Answer: 600 J

Explanation:

By definition, the work is the process due to which an applied force causes a mass to move, and can be calculated as the product of the component of the force applied along the direction of the movement, times the distance traveled.

In this case, is W= F*d= 50 N*12 m= 600 J

It can be showed, that the work done on the mass (in absence of friction ) is equal to the change in the kinetic energy of the mass.

If the roller is initially at rest, this means the following:

ΔK= 1/2 m * vf²

Now, applying Newton's 2nd Law, F=m*a ⇒ a= F/m= 3.33 m/s²

If vo=0, we can write the following:

vf²=2*a*x= 2*3.33 m/s²*12m=79.98 m²/s²

Replacing in ΔK, we obtain

ΔK= 1/2*15 kg* 79.98 m²/s²≈ 600 J

6 0

3 years ago

A 15,000 kg satellite is orbiting at 800 km above the Earth’s surface. What is the potential energy of the satellite?

vredina [299]

Answer:

$-8.34\times 10^{11}\ \text{J}$

Explanation:

m = Mass of satellite = 15000 kg

h = Distance above Earth = 800 km

R = Radius of Earth = 6371 km

M = Mass of Earth = $5.972\times 10^{24}\ \text{kg}$

G = Gravitational constant = $6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2$

Potential energy is given by

$U=-\dfrac{GMm}{R+h}\\\Rightarrow U=-\dfrac{6.674\times 10^{-11}\times 5.972\times 10^{24}\times 15000}{(6371+800)\times 10^3}\\\Rightarrow U=-8.34\times 10^{11}\ \text{J}$

The potential energy of the satellite is $-8.34\times 10^{11}\ \text{J}$ .

6 0

3 years ago