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andrew-mc [135]
3 years ago
10

When the concentration of a system is changed:

Chemistry
1 answer:
KIM [24]3 years ago
7 0

Answer:

The concentrations change to maintain the original value of K.

Explanation:

When the concentration of a system is changed, the system adjusts in order to preserve the original value of the equilibrium constant K.

  • The equilibrium constant is a constant at a given temperature and it is temperature dependent in nature.

According to Le Chatelier's principle;

  • If any conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change.
  • Stress due to any of pressure, temperature and concentration changes displaces the equilibrium.
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Answer:

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A sample of 1.000 g of a compound containing carbon and hydrogen reacts with oxygen at elevated temperature to yield 0.692 g H₂O
ollegr [7]

Answer :

(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon and hydrogen respectively.

We are given:

Mass of CO_2=3.381g

Mass of H_2O=0.692g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, \frac{12}{44}\times 3.381=0.922g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.692 g of water, \frac{2}{18}\times 0.692=0.0769g of hydrogen will be contained.

Thus, 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) Now we have to determine the compound contain any other elements or not.

Mass carbon + Mass of hydrogen = 0.922 g + 0.0769 g = 0.999 g ≈ 1 g

This means that there is no other element present in the compound.

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3 years ago
Determine the mass of 2.75 moles of CaSO4. Record your work and your answer.
maw [93]

Explanation:

RFM \:  = 160 \: g \\ 1 \: mole \: weighs \: 160 \: g \\ 2.75 \: moles \: weighs \:  \frac{2.75 \times 160}{1} g \\  = 440 \: g

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How do i write a report about Gold mining?
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<u><em>Introduction:Brings the main idea,Must be atleast 3 sentences.</em></u>
<u><em>Body/Details:Supports the main Idea,Must be atleast 8 sentences.</em></u>
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3 years ago
Calcula la cantidad de gramos que hay en 12,5 mol de NaCl (Masa Na: 23,0; Cl: 35,5).
Anon25 [30]

Answer:

731.25 g

Explanation:

The question asks us to calculate the mass of 12.5 moles of NaCl. The individual relative atomic masses of the elements were supplied. We must first obtain the molar mass of sodium chloride as follows;

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From the formula;

Number of moles (n) = mass /molar mass

Number of moles of sodium chloride= 12.5 moles

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Molar mass of sodium chloride= 58.5gmol-1

Mass of sodium chloride= number of moles × molar mass

Mass of sodium chloride= 12.5 × 58.5

Mass of sodium chloride= 731.25 g

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3 years ago
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