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kotegsom [21]
3 years ago
14

he combustion of propane (C3H8) is given by the balanced chemical equation C_3H_8+5O_2\longrightarrow3CO_2+4H_2O C 3 H 8 + 5 O 2

⟶ 3 C O 2 + 4 H 2 O How many grams of carbon dioxide gas (CO2) are produced burning 97 g of propane? Round your answer to the nearest gram.
Chemistry
1 answer:
Basile [38]3 years ago
4 0

Answer:

290 grams

Explanation:

Let's begin by writing the balanced chemical equations:

C_{3}H_{8} +5O_{2} --->3CO_{2} +4H_{2}O

Then we calculate the number of moles in 97g of propane.

n(propane)=\frac{mass}{molarmass} =\frac{97g}{44.1g/mol}=2.1995mol

According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.

n(carbon dioxide)= 2.1995mol*3 = 6.5985mol

mass(carbon dioxide) = moles * molar mass

                                   = 6.5985 mol * 44.01 g/mol

                                   = 290 grams

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3 years ago
How does the law of conservation of mass apply to this reaction: Mg + HCl > H2 + MgCl2 ?​
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Answer:

Explanation:

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Chemical equation:

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Balanced chemical equation:

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