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ExtremeBDS [4]
3 years ago
13

.i need help with math

Mathematics
2 answers:
BigorU [14]3 years ago
8 0

Answer: math is broad so which section do you need help with

Step-by-step explanation:

Setler [38]3 years ago
6 0

What’s the question?
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X+2y=0<br> 3x+4y=4<br><br> find the solution
Nady [450]

Answer:

  (x, y) = (4, -2)

Step-by-step explanation:

The coefficient of y in the second equation is double the coefficient of y in the first. We can subtract twice the first equation from the second to eliminate y.

  (3x +4) -2(x +2y) = (4) -2(0)

  x = 4 . . . . . . . . . simplify

Substituting into the first equation, we have ...

  4 +2y = 0

  2 +y = 0 . . . . . . divide by 2

  y = -2 . . . . . . . . subtract 2

The solution is (x, y) = (4, -2).

4 0
2 years ago
Place these real numbers in ascending order
Elena-2011 [213]

Answer:

1*1+4+5+3+6+3+2(6+3+4(+3+5(8+2+8+483+4+8+82+7-74-4-3

6 0
3 years ago
Anybody know the answer?
Reika [66]

I’m pretty sure it should be cos + cos

6 0
3 years ago
Write an inequality that represents 10 less than a 4 times a number more than 10,000
OLga [1]
10-4×>10,000??? I'm sorry Im not good at math
4 0
3 years ago
Read 2 more answers
What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5
Paha777 [63]
\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}&#10;\\\\\\&#10;\textit{so our LCD will just be (n+4)(n+2)}&#10;\\\\\\&#10;\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}&#10;\\\\\\&#10;\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}&#10;\\\\\\&#10;\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}&#10;\implies &#10;\cfrac{-n^2-n+2}{(n+4)(n+2)}&#10;\\\\\\&#10;\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}
3 0
3 years ago
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