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Effectus [21]
3 years ago
7

What volume of methanol should be used to make 1.25 L of a 21.0% by volume solution? ___ mL

Chemistry
1 answer:
o-na [289]3 years ago
5 0

Answer:

V CH3OH = 262.5 mL

Explanation:

  • %v/v = (v compound / v sln)×100

∴ %v/v = 21.0 %

∴ v sln = 1.25 L

⇒ v compound = ?

⇒ 21.0 % = ( v compound / 1.25)×100

⇒ 0.21 = v compound / 1.25 L

⇒ (0.21)*(1.25 L) = v compound

⇒ v compound = 0.2625 L = 262.5 mL

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Orlov [11]

Explanation:

A chemical property is defined as the property that brings changes in chemical composition of a substance.

For example, flammability, combustion, reactivity, electronegativity etc are allchemical properties.

On the other hand, a property that does not bring any change in chemical composition of a substance is known as a physical property.

For example, shape, size, mass, density etc are all physical properties.

Thus, we can conclude that these may all be classified as chemical properties of a substance.

5 0
3 years ago
Read 2 more answers
Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

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8 0
1 year ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
Willa holds a pan over a campfire, as shown in the figure below. She feels warmth from the fire.
GarryVolchara [31]

Answer:

thermal radiation/ transfer of heat

6 0
3 years ago
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What would happen when a substance changes from one phase to another? A. The substance loses or gains heat. B. The average kinet
lutik1710 [3]
I think the correct answer from the choices listed above is option B. When a substance changes from one phase to another, the average kinetic energy of the substance <span>changes since the molecules movements are changed as well. Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
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