The computation shows that the voter is the first to receive both items is A. the 42nd voter.
<h3>How to compute the value?</h3>
From the information, the candidates running for office are handing out items to voters as every 6th voter gets a button while every 7th voter gets a sticker.
Therefore, it should be noted that the least common multiple of both 6 and 7 is 42. Therefore, the voter is the first to receive both items is the 42nd voter.
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Answer:
The distribution of scores on this final exam is left-skewed.
Step-by-step explanation:
We use the Pearson Mode Skewness to solve this question. It states that:
If the median is higher than the mean, the distribution is left-skewed.
If the median is lower than the mean, the distribution is right-skewed.
If the median is the same as the mean, the distribution is symmetric.
In this problem, we have that:
Median = 74
Mean = 70
Median higher than the mean
So the distribution of scores on this final exam is left-skewed.
<span>sin θ = opposite/hypotenuse
P(18,24) lies in the first quadrant as both are positive.
x=18
y=24
Hypotenuse = sqrt (18^2 + 24^2)
</span><span>Hypotenuse = 30
</span><span>sin θ = 24/30
</span><span>sin θ = 4/5
</span>θ = sin^-1 (4/5)
<span>θ = 53.13 degrees</span>
The bottle rotates 180 degrees in 2 seconds.
I divided 270 by 3, which was 90. Then, I multiplied 90 by 2. Which was 180.<span />
