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Lady bird [3.3K]
3 years ago
9

Which leg is adjacent to be ?

Mathematics
1 answer:
LiRa [457]3 years ago
7 0
Answer b - Line BC... The adjacent line is the one directly across from the letter in question.
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Geometryyy pls help ty
zimovet [89]
16-~7 make sure to leave the power 5 out
3 0
3 years ago
Read 2 more answers
Area of a trapezium​
melamori03 [73]

Answer:

The area of a trapezium is computed with the following formula: Area = 1 2 × Sum of parallel sides × Distance between them.

Step-by-step explanation:

Hope it help! :)

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Given the points (0,6) and (2,8), what is the equation of the line
Citrus2011 [14]

Answer:

y=x+6

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(8-6)/(2-0)

m=2/2

m=1

y-y1=m(x-x1)

y-6=1(x-0)

y-6=x-0

y-6=x

y=x+6

3 0
4 years ago
What is the area of BCD?
lbvjy [14]

Answer:

36

Step-by-step explanation:

The length is 12, and the height is 6

A = 1/2 * b*h

So area = 1/2 * 72 = 36

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
3 years ago
A ball is launched straight up in the air from a height of 6 feet. Its velocity (feet/second) t seconds after launch is given by
german

Step-by-step explanation:

A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :

f(t) = -32 t+285

Height of the ball is :

h(t)=\int\limits{f(t){\cdot} dt}\\\\h(t)=\int\limits{(-32t+285){\cdot} dt}\\\\h(t)=-16t^2+285t+C

C is constant. Here the ball is launched from a height of 6 feet. So,

h(t)=-16t^2+285t+6

At t = 2 s, h(t)=-16(2)^2+285(2)+6=512\ m

At t = 9 s, h(t)=-16(9)^2+285(9)+6=1275\ m

Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.

6 0
4 years ago
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