Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
Answer:
I think his age is 39.
Step-by-step explanation:
If Cesar's age was 2 times Rosa's 6 years ago, that means their combined ages 6 years ago was 66. 66 dived by 2 is 33 and 33 plus the 6 years is 39.
Turn the question around.
If all the numbers were positive: 2.5, 1.6, 3 1/10, 1/10, and 0.5, which would be farthest to the right?
The fact is that the negative numbers are a reflection of the positive numbers.
Since 3 1/10 would be farthest to the right with positive numbers, -3 1/10 will be farthest to the left with the negative numbers.
Answer:
60m/s
Step-by-step explanation:
velocity of the while moving is 30 m/s and it becomes 90 m/s after speeding up at constant rate. so the average velocity of the journey is
[90+30] /2
=60 m/s
Answer:
Step-by-step explanation:
Given;
(a) y = tan(5t)
Solving for (a)
y = tan(5t)
let u = 5t
⇒y = tan(u)
du/dt = 5
dy/du = sec²u
Solving for b;
let u = 5 - v²
du/dv = -2v
let v = 5+ v²
dv/du = 2v
