Answer and explanation:
Farmer's number of apples = 96 apples
Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag
And also all apples in each bag are equal
We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder
4 can divide 96= 24
5 cannot divide 96 without remainder
6 can divide 96 =16
7 cannot divide 96 without remainder
8 can divide 96=12
9 cannot divide 96 without remainder
10 cannot divide 96 without remainder
From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10
4 apples = 24 bags
6 apples = 16 bags
8 apples = 12 bags
Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples
Hello,
After decrypting the question:
f(x)=2x^4-4x^3-11x^2+3x-6
f(-2)=2(-2)^4-4(-2)^3-11(-2)^2+3*(-2)-6=2*16+32-44-6-6=8
Answer
<2 = <4 = <6 = <8
All of those are 94 degrees
<1 = <3 = <5 + <7
All of those are 86 degrees
Hope this helps :D
Answer:
0
Step-by-step explanation:
2a(b−c)+b(2c−2a)+4c(0.5a−0.5b)
To simplify this we need to remove the parenthesis
Distribute 2a, b and 4c inside the parenthesis
2ab -2ac + 2bc - 2ab + 2ac - 2bc
now we combine like terms'
2ab - 2ab becomes 0
-2ac +2ac becomes 0
+2bc - 2bc becomes 0
So final answer is 0
