In which direction will the object accelerate?

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimum coefficient of static friction

DanielleElmas [232]

Answer:

The minimum coefficient of static friction between the road and the car's tires is 0.816

Option "C"

Explanation:

Given;

velocity of the car, v = 40.0 m/s

radius of horizontal curve, r = 200 m

For a minimum coefficient of static friction between the road and the car's tires that will allow the car to travel at the given speed without sliding, centripetal force must equal frictional force.

$F_{frictional} = F_{centripetal}\\\\\mu mg = \frac{mv^2}{r} \\\\\mu = \frac{v^2}{rg}$

where;

μ is the minimum coefficient of static friction

$\mu = \frac{40^2}{200*9.8} \\\\\mu = 0.816$

Thus, the minimum coefficient of static friction between the road and the car's tires is 0.816

Option "C"

3 0

2 years ago

Solar cells are often coated with a transparent, thin film of silicon monoxide (n = 1.45) to minimize reflective losses from the

Alinara [238K]

Answer:

94.82 nm

Explanation:

We have given that wavelength $\lambda=550\ nm$

We have to find the minimum film thickness that produces the least reflection

minimum thickness is given by $t=\frac{\lambda }{4n}$

here n is given n=1.45

so minimum thickness $t=\frac{550 }{4\times 1.45}=94.82\ nm$

so the minimum film thickness will be 94.82 nm

7 0

3 years ago

NEEDD SOME HELP ASAP HELP MEHHH<br> 50 pOINTS

Vadim26 [7]

An electron shell can hold 2(n^2) electrons (technically) where n is the shell number, i.e. shell 1 can hold 2, shell 2 can hold 8, 3 holds 18 and so on.
The atomic number of Nitrogen is 7, i.e. it has 7 electrons (to match its 7 protons, assuming it isn't an ion).

With the atomic number, you simply start from shell 1 and work out. So we put 2 electrons in shell 1, leaving us with 5 left. Shell 2 can hold 6 so we can fit all 5 in.

In other words, you should have 2 electron shells on the atom, shell 1 with 2 e- and shell 2 with 5 e-.

3 0

2 years ago

Read 2 more answers

The stopwatch used by a student to measure velocity of a pulse in a slinky was of least count 0.1 second. He stops the stopwatch

sweet-ann [11.9K]

Least count of the pulse stopwatch is given by

$\Delta t = 0.1 s$