Question

What is the efficiency of a device that takes in 400 J of heat and does 120 J

Answer 1

The efficiency of the device is 30 %

Explanation:

The efficiency of a heat engine is given by:

$\eta = \frac{W}{Q_{in}}$

where

W is the work done by the engine

$Q_{in}$ is the heat in input to the engine

For the device in this problem, we have:

W = 120 J is the work done

$Q_{in} = 400 J$ is the heat in input

Substituting, we find the efficiency:

$\eta=\frac{120}{400}=0.30$

which corresponds to an efficiency of 30%.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

Answer 2

Answer: 30%

Explanation: