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bekas [8.4K]
3 years ago
11

What is the efficiency of a device that takes in 400 J of heat and does 120 J

Physics
2 answers:
777dan777 [17]3 years ago
7 0

The efficiency of the device is 30 %

Explanation:

The efficiency of a heat engine is given by:

\eta = \frac{W}{Q_{in}}

where

W is the work done by the engine

Q_{in} is the heat in input to the engine

For the device in this problem, we have:

W = 120 J is the work done

Q_{in} = 400 J is the heat in input

Substituting, we find the efficiency:

\eta=\frac{120}{400}=0.30

which corresponds to an efficiency of 30%.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

Alinara [238K]3 years ago
4 0

Answer: 30%

Explanation:

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