Answer:
<h2>9.8 m/s²</h2>
Explanation:
<h2>Since the ball rises for 2.5 s, the time to fall is 2.5 s. The acceleration is 9.8 m/s2 everywhere, even when the velocity is zero at the top of the path. Although the velocity is zero at the top, it is changing at the rate of 9.8 m/s² downward.</h2>
Answer:
Isotope it will have a different number of neutrons than normal
Answer:
276.135 J
Explanation:
Given that:
mass of Fe = 30.0 g
initial temperature = 24.5°C
final temperature = 45.0°C
specific heat of Fe = 0.449 J/g°C
We can determine the thermal energy added by using the formula;
Q = mcΔT
Q = 30.0g × 0.449 J/g°C × (45.0 - 24.5)°C
Q = 276.135 J
Answer:
according to the new geometry lesson alcometry which will after 11 years in geometry
Answer:
8.6 miles
Explanation:
We need to calculate the components of the total displacement along the east-west and north-south directions first.
In the first part, Erica moves 5.2 miles at 25∘ north of east. So the components of this displacement along the two directions are:
East: 
North: 
In the second part, Erica moves 5.0 miles north. So, the components of this displacement are:
East: 
North: 
So the components of the total displacement are
East: 
North: 
Therefore the magnitude of the displacement, which is the straight-line distance from the starting point to the end of the race, is
