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soldi70 [24.7K]
3 years ago
5

How many Joules are present in 7401 kJ?

Chemistry
1 answer:
Marianna [84]3 years ago
7 0

Answer:

74010000 J

Explanation:

7401 KJ

= 7401 × 1000

= 74010000 J

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4P+ 5O2 -> P4O10
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If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2

so .611 moles

so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
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so first ans is .611 moles and second is 34.7 grams !

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