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A vacuum tube can be used to__. A. change alternating current into direct current B. increase the strength of a signal.. C. turn

vesna_86 [32]

The correct answer of this question is : A) Change alternating current into direct current.

EXPLANATION :

As per the question, we are given vacuum tube. Vacuum tube can be of various types. Normally it contains two electrodes called cathode and anode which are enclosed in an evacuated glass chamber . There are also other types of vacuum tubes which contain extra electrodes like control grid .

The vacuum tube can be used as a rectifier. It means that it can be used as an electronic device which will convert alternating current into direct current. It may be a half wave rectifier or a full wave rectifier. Actually the direct current obtained during the rectification of alternating current is pulsating in nature.

Hence, the correct answer is that a vacuum tube can be used to change alternating current into direct current.

4 0

3 years ago

Read 2 more answers

Circuit diagram showing three resistors in series with an ammeter,a cell and a switch

docker41 [41]

Answer:

the mayflower

Explanation:

4 0

3 years ago

A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck

Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

$M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing})$ where $M_{truck}$ is the mass of the truck, $V_{truck}$ is velocity of the truck, $V_{common}$ is the common velocity of moving and standing truck after collision and $M_{standing}$ is the mass of the standing truck

Making $V_{truck}$ the subject we obtain

$V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}$

Substituting $M_{truck}$ as 25000 Kg, $V_{common}$ as 22.3 m/s, $M_{standing}$ as 2000 Kg we obtain

$V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s$

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0

3 years ago

A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai

tekilochka [14]

Answer:

900 W.

Explanation:

Given that

Electric heater 1500 W

We know that power P given as

P= V I

So the total power of 120 V and 20 A circuit

P = 120 x 20

P= 2400 W

So the power new load P'

P'= Total system power(P)- Electric heater load

P ' = 2400 - 1500

P'= 900 W

So the answer is 900 W.

6 0

3 years ago

Which factors are used to calculate the kinetic energy of an object?

kipiarov [429]

Answer:The factors which are used to calculate the kinetic energy of an object are mass and velocity. Explanation: The kinetic energy is the energy of the motion of an object. Here, m is the mass of the object and v is the velocity of the object.

Explanation:

hope it helps

3 0

3 years ago