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steposvetlana [31]
3 years ago
15

Looking for new information is one reason you should do research for a speech.

Engineering
2 answers:
bearhunter [10]3 years ago
8 0
I agree with the other person. i believe the answer is false.
ValentinkaMS [17]3 years ago
4 0
The correct answer is False
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15- Vipsana's Gyros House sells gyros. The cost of ingredients (pita, meat, spices, etc.) to make a gyro is $2.00. Vipsana pays
sineoko [7]
D is a great answer
4 0
3 years ago
Air at 38°C and 97% relative humidity is to be cooled to 14°C and fed into a plant area at a rate of 510m3/min. (a) Calculate th
Katarina [22]

To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.

The gas ideal law is given as,

PV=mRT

Where,

P = Pressure

V = Volume

m = mass

R = Gas Constant

T = Temperature

Our data are given by

T_1 = 38\°C

T_2 = 14\°C

\eta = 97\%

\dot{v} = 510m^3/kg

Note that the pressure to 38°C is 0.06626 bar

PART A) Using the ideal gas equation to calculate the mass flow,

PV = mRT

\dot{m} = \frac{PV}{RT}

\dot{m} = \frac{0.6626*10^{5}*510}{287*311}

\dot{m} = 37.85kg/min

Therfore the mass flow rate at which water condenses, then

\eta = \frac{\dot{m_v}}{\dot{m}}

Re-arrange to find \dot{m_v}

\dot{m_v} = \eta*\dot{m}

\dot{m_v} = 0.97*37.85

\dot{m_v} = 36.72 kg/min

PART B) Enthalpy is given by definition as,

H= H_a +H_v

Where,

H_a= Enthalpy of dry air

H_v= Enthalpy of water vapor

Replacing with our values we have that

H=m*0.0291(38-25)+2500m_v

H = 37.85*0.0291(38-25)-2500*36.72

H = 91814.318kJ/min

In the conversion system 1 ton is equal to 210kJ / min

H = 91814.318kJ/min(\frac{1ton}{210kJ/min})

H = 437.2tons

The cooling requeriment in tons of cooling is 437.2.

3 0
3 years ago
The symmetrical load below is connected to a three-phase network. A line current of 25A has been measured. The load resistors ha
boyakko [2]

Answer:

The line voltage of the three phase network is 346.41 V

Explanation:

Star Connected Load

Resistance, R₁ = R₂ = R₃ = 18 Ω

For a star connected load, the line current = the phase current, that is we have

I_L = 25 \, A =  I_{Ph}

Whereby the the voltage across each resistance = V_R is given by the relation;

V_R = I_{Ph} × R

Hence;

V_{Ph} = V_R = I_{Ph} × R  = 25 × 8 = 200 V

Therefore we have;

The line voltage, V_{L} = √3 × V_{Ph} = √3 × 200 = 346.41 V.

Hence, the line voltage of the three phase network = 346.41 V.

3 0
4 years ago
The name of a round stock welding position refers to the
Sedaia [141]
Charlidamelio is overrated
3 0
3 years ago
Read 2 more answers
List three examples of waves that can transfer energy without going through a medium
Finger [1]

Electromagnetic waves can transfer energy without a material medium.

3 examples of elctromagnetic energy include: Radio wave, X-rays and gamma rays

<h3>What is wave?</h3>

A wave is a disturbance that transfers energy from one point to another.

Electromagnetic waves are waves that does not require a material medium for the tranfer of energy

  • Radio wave
  • Gamma rays
  • X-rays
  • Light wave

Read more on Electromagnetic waves here: brainly.com/question/13874687

7 0
3 years ago
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