Calcium Carbonate + Hydrochloric Acid
CaCO₃ +HCl ⇒ CaCl₂ + H₂O + CO₂
Answer:
Explanation:
Hello,
In this case, we can consider the n-propanol as the solute (lower amount) and the t-butanol as the solvent (higher amount), for which, initially, we must compute the moles of n-propanol (molar mass = 60.1 g/mol) as shown below:
Since the molality is computed via:
Whereas the mass of the solvent is used in kilograms (0.0130g for the given one). Thus, we compute the resulting molality of the solution:
Or just:
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The ballon would probably catch on fire
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Answer:
Density = 2.137 gram per liter (Approx.)
Explanation:
Given:
Gaseous fuel Butane C4H10
Pressure = 0.897 atm
Temperature = 24°C = 24 + 273 = 297 k
Find:
Density of butane gas
Computation:
We know that molar mass of butane = 58.12 g/mol
Density = [molar mass x pressure] / Rt
Density = [58.12 x 0.897] / [0.0821 x 297]
Density = [52.13] / [24.3837]
Density = 2.137 gram per liter (Approx.)
