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rodikova [14]
3 years ago
6

Upon being struck by 240-nm photons, a metal ejects electrons with a maximum kinetic energy of 1.45 eV. What is the work functio

n of this metal? (A) 3.73 eV (B) 3.13 eV (C) 4.33 eV (D) 4.92 eV
Physics
1 answer:
Bess [88]3 years ago
3 0

Answer:

W = 3.73 eV

Explanation:

Given data:

wavelength of photons 240 nm

kinetic energy 1.45 eV

B y using photoelectric equation

Kinetic Energy  =  Photon Energy - work friction

K.E = \frac{hc}{\lambda} -W

\frac{hc}{\lambda} = \frac{6.63\times 10^{-34}\times 3\times 10^8}{240\times 10^{-9}\times 1.6\times 10^{-19}} eV

                              = 5.179 eV

                              = 5.18 eVW =  \frac{hc}{\lambda} - K.E

    = (5.18 - 1.45) eV

W = 3.73 eV

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