Answer:
123 km/h
Explanation:
The distance between the Jeep Wrangler and the Ford Taurus is increasing.
Let us consider the north direction as positive when observing from the ground
So, the south direction will be negative
But when the observer is one of the cars the direction will be the same i.e., moving away from each other, so the velocity will be added.
Hence velocity of the Jeep relative to the Ford will be
Velocity of the Jeep + Velocity of the Ford
= 74+49 = 123 km/h
∴ Velocity of the Jeep relative to an observer in the Ford is 123 km/h
Answer:
9800 Pa
Explanation:
Data: pressure-?
Force- mass ×acceleration
= 50× 9.8m/s^2
=490N
Area= 500cm^2=0.05m^2
pressure= force/ area
p=F/A
P= (490N)/( 0.05m^2)
=9800 Pa
Answer:
The thrust of the jet engine is 4188.81 N.
Explanation:
Given that,
Speed = 260 m/s
Rate in air= 53.3 kg/s
Rate of fuel = 3.63 kg/s
Relative speed = 317 m/s
We need to calculate the rate of mass change in the rocket
Using formula of rate of mass
Put the value into the formula
We need to calculate the thrust of the jet engine
Using formula of thrust
Put the value into the formula
Hence, The thrust of the jet engine is 4188.81 N.
Answer:
initial velocity is the constant in horizontal projectile
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