Given that the mass of coffee in the cup = 140 g
Final temperature = 
Initial temperature = 
Let us assume the specific heat of coffee is equal to that of water = 4.184
Temperature change = T(final) - T(initial) = (20 - 75 )
=- 55
-Heat given out by coffee = heat absorbed by the surroundings
Heat released into the surroundings =-(
)
= 
= 32,217 J
Answer: pOH = 3.13
Ba(OH)2 is a very basic substance. The general formula for pOH is - log(OH)
Barium Hydroxide produces 2 moles of OH for every mole of Ba(OH)2 present in the solution.
0.00037 M = 3.7 * 10^-4 Ba(OH)2 will produce 2 *0.00037 M of OH-
OH- = 2* 0.00037 = 0.00074
pOH = - log(0.00074) = 3.13
Answer:
The solution to this question can be defined as follows:
Explanation:
The complete question is defined in the attached file.
Here:
I think it maybe 59.7852%
Answer:
Because we need to dispense 4.7 mL, the volume reading in the pipet is the 5.3 mL line.
Explanation:
First we use C₁V₁=C₂V₂ in order to <u>calculate the required volume of concentrated HCl</u> (V₁):
12.85 M * V₁ = 0.600 M * 100 mL
V₁ = 4.7 mL
<u>So we need to dispense 4.7 mL of the concentrated HCl solution</u>. The mark in the pipet that would contain that volume would be 10.0 - 4.7 = 5.3 mL
