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Nataliya [291]
3 years ago
14

A 50g ball is falling down. As the ball passes a certain distance its potential energy changes for 2J. Calculate this distance.

Does this distance depend on the initial velocity of the ball?
Physics
1 answer:
Paul [167]3 years ago
8 0

potential energy = mass × gravity × height

so, change in potential energy = mass × gravity × change in height

2 = 50 × 10 × Δh

2 ÷ 500 = Δh

Δh = 0.004 m

This distance does depend on the initial velocity of the ball.

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nignag [31]

Answer:

a) x = 40 t , y = 39 t ,  z = 6 + 32 t - 16 t ²,   b)     x = 80 feet ,  y = 78 feet , the ball came into the field  

Explanation:

a) This is a projectile launch exercise, where in the x and y axes there is no acceleration and in the z axis the acceleration of the acceleration of gravity, let's write the equations of motion in each axis

Since the cast is in the center of the field, let's place the coordinate system

          x₀ = 0

          y₀ = 0

          z₀ = 6 feet

x-axis (towards end zone,  GOAL zone)

         x = xo + v₀ₓ t

        x = 40 t

y-axis (field width)

        y = y₀ + v_{oy} t

        y = 39 t

z axis (vertical)

        z = z₀ + v_{oz} t - ½ g t²

        z = 6 + 32 t - ½ 32 t²

        z = 6 + 32 t - 16 t ²

b) The player catches the ball at the same height as it came out, so we can find the time it takes to arrive

          z = 6

          6 = 6 + 32 t - 16 t²

          (t - 2)t  = 0

           t=0 s

           t= 2 s

The ball position

          x = 40 2

          x = 80 feet

           

          y = 39 2

          y = 78 feet

the dimensions of the field from the coordinate system (center of the field) are

             x_total = 150 feet

             y _total = 80 feet

so we can see that the ball came into the field

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Answer:

Explanation:

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Alina [70]
Weight? I’m not sure
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spayn [35]

Explanation:

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Answer:

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Explanation:

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