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Nataliya [291]
3 years ago
14

A 50g ball is falling down. As the ball passes a certain distance its potential energy changes for 2J. Calculate this distance.

Does this distance depend on the initial velocity of the ball?
Physics
1 answer:
Paul [167]3 years ago
8 0

potential energy = mass × gravity × height

so, change in potential energy = mass × gravity × change in height

2 = 50 × 10 × Δh

2 ÷ 500 = Δh

Δh = 0.004 m

This distance does depend on the initial velocity of the ball.

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A hockey puck is struck so that it slides at a constant speed and strikes the far side of the rink, 58.2 m away. The shooter hea
DENIUS [597]

Answer:

v = 33.66 m/s

Explanation:

Let hockey puck is moving at constant speed v

so here we have

d = vt

so time taken by the puck to strike the wall is given as

t = \frac{58.2}{v}

now time taken by sound to come back at the position of shooter is given as

t_2 = \frac{58.2}{340}

t_2 = 0.17s

so we know that total time is 1.9 s

1.9 = t + t_2

1.9 = t + 0.17

1.9 - 0.17 = t

t = 1.73 s

now we have

1.73 = \frac{58.2}{v}

v = 33.66 m/s

7 0
3 years ago
What location on earth experiences the most change the number of daylight hours?
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3 0
4 years ago
action and reaction are equal in magnitude and opposite direction then why they don't balance each other
Harrizon [31]
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Hope you understood...
8 0
3 years ago
An airplane flew 1000 m in 400 seconds. What is the airplane's speed?
weqwewe [10]

Answer:

speed =  \frac{distance}{time}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  \frac{1000}{400}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 2.5m {s}^{ - 1}

6 0
3 years ago
Read 2 more answers
What is the magnitude of the angular momentum (in kgm2/s) of a 40 g golf ball flying through the air and spinning at 4300 rpm af
sladkih [1.3K]

Answer:

L=0.0045\ kg-m^2/s

Explanation:

Given that,

The mass of a golf ball, m = 40 g = 0.04 kg

Its angular velocity, \omega=4300\ rpm=450.29\ rad/s

The radius of the sphere is 2.5 cm or 0.025 m

We need to find the magnitude of the angular momentum of the ball. It is given by the formula as follows:

L=I\omega

Where I is moment of inertia

For sphere, I=\dfrac{2}{5}mr^2

L=\dfrac{2}{5}mr^2\omega\\\\L=\dfrac{2}{5}\times 0.04\times (0.025)^2\times 450.29\\\\L=0.0045\ kg-m^2/s

So, the magnitude of the angular momentum of the sphere is 0.0045\ kg-m^2/s.

4 0
3 years ago
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