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lorasvet [3.4K]
3 years ago
13

Which of the following elements has the highest electronegativity? beryllium iodine calcium nitrogen

Chemistry
2 answers:
juin [17]3 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

An atom or element which has the ability to readily gain an electron will have high electronegativity.

Both Beryllium and Calcium are alkaline earth metals and hence they are electropositive in nature.

Whereas both iodine and nitrogen are electronegative in nature. But across the period there is an increase in electronegativity and down the group there is a decrease in electronegativity.

Nitrogen belongs to period 2 and iodine belongs to the bottom of group 17. Thus, we can conclude that nitrogen is more electronegative than iodine.

ikadub [295]3 years ago
7 0

Answer:

The correct option is: D. nitrogen                    

Explanation:

Electronegativity is the capability of a chemical element to attract or pull the bond pair involved in the formation of a covalent bond towards itself.

As the atomic radius of an element increases, its tendency to attract the bond pair towards itself decreases. Therefore, the electronegativity decreases.

Since in the periodic table, the <u>atomic radius increases down a group and generally decreases across a period</u>. So, <u>the electronegativity decreases down the group and generally increases across a period.</u>

Therefore, Nitrogen which belongs to period 2 and group 15 of the periodic table, has the <u>smallest atomic radius </u>among the given chemical elements <u>and thus is the most electronegative element (3.04 on the Pauling scale)</u> among the given chemical elements.  

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Iron(II) sulfate, an iron supplement , FeSO4 Express your answer to four significant figures and include the appropriate units.
strojnjashka [21]

Answer:

Molar mass = 151.9 g/mol

Explanation:

The molar mass of a compound is obtained by adding u the individual atomic masses in the compound. The unit is g/mol.

In FeSO4, we have one Fe, one S and 4 O.

The atomic masses are given as follows;

Fe = 55.845 u

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O = 15.999 u

Molar mass = ( 1 * Fe) + (1 * S) + (4 * O)

Molar mass = (1 * 55.854 ) + ( 1 * 32.065) + (4 * 15.999)

Molar mass = 151.915  g/mol

In four significant figures;

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3 years ago
The diameter of the He He atom is approximately 0.10 nm nm . Calculate the density of the He atom in g/cm 3 g/cm3 (assuming that
Sladkaya [172]

Answer:

Density of the He atom = 12.69 g/cm³

Explanation:

From the information given:

Since 1 mole of an atom = 6.022x 10²³ atoms)

1 atom of He = 1  \ atom \times  (\dfrac{1  \ mole}{  6.022 \times  10^{23}  \ atoms}) \times ( \dfrac{4.003 \ grams}{  1  \ mole})

=6.647 \times  10^{-24} \  grams

The volume can be determined as  folows:

since the diameter of the He atom is approximately 0.10 nm

the radius of the He = \dfrac{0.10}{2} = 0.05 nm

Converting it into cm, we have:

0.05 nm \times  \dfrac{10^{-9} \  meters}{ 1  nm} \times \dfrac{ 1 cm }{10^{-2} \ meters}

=5 \times  10^{-9}  \ cm

Assuming that it is a sphere, the volume of a sphere is

= \dfrac{4}{3}\pi r^3

= \dfrac{4}{3}\pi  \times (5\times 10^{-9})^3

= 5.236 \times 10^{-25} \ cm^3

Finally, the density can be calcuated by using the formula :

Density = \dfrac{mass}{volume}

D =  \dfrac{6.647 \times  10^{-24} \  grams }{ 5.236 \times 10^{-25} \  cm^3}

D = 12.69 g/cm³

Density of the He atom = 12.69 g/cm³

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