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Ipatiy [6.2K]
3 years ago
11

How many atoms are in 200.0 grams of Sulfur (S)?

Chemistry
1 answer:
Mama L [17]3 years ago
4 0

Answer:

37.64 × 10²³ atoms

Explanation:

Given data:

Number of atoms = ?

Mass of sulfur = 200.0 g

Solution:

First of all we will calculate the number of moles of sulfur.

Number of moles = mass/molar mass

Number of moles = 200.0 g/ 32 g/mol

Number of moles = 6.25 mol

Number of atoms:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

6.25 mol × 6.022 × 10²³ atoms / 1mol

37.64 × 10²³ atoms

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A sample of natural rubber (200.0 g) is vulcanized, with the complete consumption of 4.8 g of sulfur. Natural rubber is a polyme
nasty-shy [4]

Answer: 1.3% many crosslinks as isoprene units,  

Explanation:

Given:

mass pf natural rubber= 200.0g

mass of sulphur = 4.8g

molar mass of sulphur =32g/mol

molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol

Solution: we first find no of moles present in each  using

no of moles = \frac{mass}{molarmass}

Isoprene: 200.0g x [1mole / 68g] = 2.94moles.

Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.

to find % crosslinked units, we have  

0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,  

3 0
3 years ago
In an experiment, a solution required 30. 05 g of nacl, 50. 0 g of , and 0. 4006 g of mgso4. Using the correct number of signifi
Radda [10]

When the use of significant figures and rounding up is applied correctly the mass of the mixture will be 80.5 g.

In cases of addition or subtraction, only the last significant figure of every number is taken into account.

In 30.05, this is 5, in the hundredths. When we look at 50.0, the last significant figure is 0, and it is in the tenths. And in 0.4006, the last significant figure is 6, in the ten thousandths. Of these three, the 0 from 50.0 is in the leftmost position, which means that the last significant figure of the result needs to be in the same position (in the tenths).

Moving onto the actual algebraic operation:

30.05 g + 50.0 g + 0.4006 = 80.4506 g

As we established, the last significant figure should be in the tenths, and we will have to round up 4 to 5 (trailing numbers are greater than 0), which means that the resulting mass will be 80.5 g.

You can learn more about significant figures here:

brainly.com/question/14804345

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7 0
2 years ago
_Al + _O2 —> _Al2O3
Kisachek [45]
4Al + 3O2 --> 2Al2O3.
6 0
3 years ago
Calculate the weight of 3.491 into 10 to the power 19 molecules of cl2​
Rom4ik [11]

Answer:

The mass of 3.491 × 10¹⁹ molecules of Cl₂  of Cl₂ is 4.11 × 10⁻³ grams

Explanation:

The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles

Therefore, we have;

One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂

3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂

The mass of one mole of Cl₂ = 70.906 g/mol

The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams

Therefore;

The mass of 3.491 × 10¹⁹ molecules of Cl₂  of Cl₂ = 4.11 × 10⁻³ grams.

4 0
3 years ago
A student wants to examine a substance without changing its identity. Which of the following properties of the substance should
Vinvika [58]

Answer:

A

Explanation:

Ductility, because it can be observed by altering the shape of the substance

3 0
3 years ago
Read 2 more answers
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