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3 years ago

How many atoms are in 200.0 grams of Sulfur (S)?

Chemistry

1 answer:

Mama L [17]3 years ago

4 0

Answer:

37.64 × 10²³ atoms

Explanation:

Given data:

Number of atoms = ?

Mass of sulfur = 200.0 g

Solution:

First of all we will calculate the number of moles of sulfur.

Number of moles = mass/molar mass

Number of moles = 200.0 g/ 32 g/mol

Number of moles = 6.25 mol

Number of atoms:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

6.25 mol × 6.022 × 10²³ atoms / 1mol

37.64 × 10²³ atoms

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A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an

mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation : Given,

Concentration of $H_2$ at equilibrium = 0.067 mol

Concentration of $CO$ at equilibrium = 0.021 mol

Concentration of $CH_3OH$ at equilibrium = 0.040 mol

The given chemical reaction is:

$CO+2H_2\rightarrow CH_3OH$

The expression for equilibrium constant is:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}$

$K_c=424.3$

Thus, the value of equilibrium constant (K) is, 424.3

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3 years ago

Dissolving salt in water reduces the intermolecular forces between water molecules. What most likely happens to the surface tens

Svetllana [295]

If we dissolve salt in water they will reduce the intermolecular forces between water molecule and this will decrease the surface tension.

Surface tension is due to cohesive forces (the forces between molecules of same substance) hence as cohesive forces decreases the surface tension also decreases

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3 years ago

Read 2 more answers

What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv

statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

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3 years ago