Explanation:
As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.
So, using ideal gas equation we will calculate the number of moles as follows.
PV = nRT
or, n = 
= 
= 0.0052 mol
Also, No. of moles = 
0.0052 mol = 
mass = 0.0104 g
As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at
= 24 mm Hg
=
atm
= 0.03158 atm
Now, P = 
= 0.963 atm
Hence, n =
= 0.0056 mol
So, mass of
= 0.0056 mol × 2
= 0.01013 g (actual yield)
Therefore, calculate the percentage yield as follows.
Percent yield = 
=
= 97.49%
Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.
B)Buenos Aires was the city near the epicenter :)
Answer:
B. 10 mL of Cabr2(aq) at 35 degrees celsius
Explanation:
The colder something is the more the atoms are compressed together; atoms can't move as much. 35 degrees is the warmest option, so it makes the most sense.
Answer:
The answer to your question is:
Explanation:
Data
carbon 7.3% = 7.3g
hydrogen 4.5% = 4.5g
oxygen 36.4% = 36.4 g
nitrogen 31.8% = 31.8 g
Now
For carbon
12 g --------------------1 mol
7.3 g ------------- x
x = 7.3/12 = 0.608 mol
For hydrogen
1 g -------------------- 1 mol
4.5 g ------------------ x
x = 4.5 mol
For oxygen
16 g ------------------- 1 mol
36.4 g ---------------- x
x = 2.28 mol
For nitrogen
14 g ---------------- 1 mol
31.8 g --------------- x
x = 2.27 mol
Now divide by the lowest result, the is 0.608 from carbon
carbon 0.608/0.608 = 1
hydrogen 4.5/ 0.608 = 7.4
oxygen 2.28/0.608 = 3.75
nitrogen 2.27/0.608 = 3.73
Empirical formula = CH₇O₄N₄