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astra-53 [7]
4 years ago
10

A dry cleaner charges $18 to clean 4 pairs of pants.   How many pairs of pants can be cleaned for $27 at the same rate?

Mathematics
1 answer:
blondinia [14]4 years ago
5 0

4 pairs of pants for $18.

Divide price by quantity to get the cost of 1 pair of pants:

18 / 4 = 4.50 per pair.


Divide 27 by 4.50 to find number of pairs:

27 / 4.5 = 6

6 pairs of pants can be cleaned for $27.

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y= -2+\frac{2}{3}x

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Evaluate tan(Sin-1(-5/13)). Answer as a fraction please.
dangina [55]

Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))

Let A = arcsin(-5/13) = -arcsin(5/13)

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
4 years ago
Find the probability that when a couple has four ​children, at least one of them is a girl. ​(Assume that boys and girls are equ
AveGali [126]

Answer:

0.9375 = 93.75% probability that at least one of the four children is a girl.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have the following sample space

In which b means boy, g means girl

b - b - b - b

b - b - b - g

b - b - g - b

b - b - g - g

b - g - b - b

b - g - b - g

b - g - g - b

b - g - g - g

g - b - b - b

g - b - b - g

g - b - g - b

g - b - g - g

g - g - b - b

g - g - b - g

g - g - g - b

g - g - g - g

Total outcomes

There are 16 total outcomes(size of the sample space)

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Of these outcomes, only 1(b - b - b - b) there is not a girl.

So the number of desired outcomes is 15.

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P = \frac{15}{16} = 0.9375

0.9375 = 93.75% probability that at least one of the four children is a girl.

7 0
3 years ago
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