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Misha Larkins [42]
3 years ago
8

a step of science investigation tells you to walk 3m in a straight line, then turn 60 degrees to your right. you repeat this ste

p until you are standing at your original position what shape have you traced?
Physics
2 answers:
IgorC [24]3 years ago
8 0

If you walk 3m in a straight line then turn 60 degrees until you are standing at your original position then you have walked a hexagon

tiny-mole [99]3 years ago
4 0

Here we can see that after moving for distance of d = 3 m it takes turn at 60 degree angle

this will continue till it comes to its own position

so it will look like a polygon

here Number of sides of polygon is given as

N = \frac{total Angle}{exterior angle}

now we will have

N = \frac{360}{60} = 6

So here we have total sides are 6

So here it will be a polygon of 6 sides

so it's shape will be a regular hexagon of each side as 3m length

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A 600 kg car is at test and then accelerated to 5m/s , what is its original kinetic energy
ycow [4]

Answer:

0 J

Explanation:

Kinetic energy is defined as:

KE = 1/2 m v²

where m is mass and v is velocity.

The car starts at rest, so it has zero velocity.  Therefore, its initial kinetic energy is 0 J.

3 0
3 years ago
What is the total distance that the object traveled?
Natasha_Volkova [10]

Answer:

for what?

Explanation:

d=S x T

or

d=vt+1/2at2

srry if wrong but

hope this helps

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8 0
3 years ago
Look at the equation. What detail is missing? 3 m/s2= (33 m/s - X)/30 S <br>​
Tems11 [23]

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}

6 0
3 years ago
An object of mass 300 g, moving with an initial velocity of 5.00i-3.20j m/s, collides with an sticks to an object of mass 400 g,
Alexus [3.1K]

Answer:

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

Explanation:

Mass of object 1 , m₁ = 300 g = 0.3 kg

Mass of object 2 , m₂ = 400 g = 0.4 kg

Initial velocity of object 1 , v₁ = 5.00i-3.20j m/s

Initial velocity of object 2 , v₂ = 3.00j m/s

Mass of composite = 0.7 kg

We need to find final velocity of composite.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = 0.3 x (5.00i-3.20j) + 0.4 x 3.00j = 1.5 i + 0.24 j kgm/s

Final momentum = 0.7 x v = 0.7v kgm/s

Comparing

1.5 i + 0.24 j = 0.7v

v = 2.14 i + 0.34 j

Magnitude of velocity      

       v=\sqrt{2.14^2+0.34^2}=2.17m/s

Direction,  

       \theta =tan^{-1}\left ( \frac{0.34}{2.14}\right )=9.03^0

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

7 0
3 years ago
Which of the following BEST describes the term "air resistance"?
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<span>BSL Physics Glossary - air resistance - definition. Translation: Air resistance is a force that is caused by air. The force acts in the opposite direction to an object moving through the air.</span><span>
</span>
8 0
3 years ago
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