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morpeh [17]
3 years ago
14

The number of electrons an atom would gain or lose when forming ionic bonds. It can be positive, negative or zero.

Physics
1 answer:
vaieri [72.5K]3 years ago
8 0

Answer:

<u>In an ionic bond , an element will have to lose or gain electrons.</u>

Explanation:

  • Ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.
  • Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.
  • <em>The atom that loses the electrons becomes a positively charged ion (cation), while the one that gains them becomes a negatively charged ion (anion).</em>

∴

  • <em>The number of electrons an atom would gain or lose when forming ionic bonds cannot be zero.</em>
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To solve this problem, we must remember about the law of conservation of momentum. The initial momentum mist be equal to the final momentum, that is:

m1 v1 + m2 v2 = (m1 + m2) v’

where v’ is the speed of impact

Since we are not given the masses of each car m1 and m2, so let us assume that they are equal, such that:

m1 = m2 = m

Which makes the equation:

m v1 + m v2 = (2 m) v’

Cancelling m and substituting the v values:

50 + 48 = 2 v’

2 v’ = 98

v ‘ = 49 km/h

 

<span>The speed of impact is 49 km/h.</span>

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3 years ago
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We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.2
monitta

Answer:

The number of atoms is N = 4.37*10^{22} \ atoms

Explanation:

From the question we are told that

                 The mass of coin  is m_n = 4.2g

                   Number of atom in one mole = n =6.02*10^{23} \ atoms

                   Molar mass of nickel M = 57.8g

Now the relation to obtain the number of atom in  the  nickel coin is

                        N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel }  * No\ of\atoms \ in \ \ one\  mole\ of\ nickel

                           = \frac{4.2}{57.8}* 6.02*10^{23}

                           =4.37 *10^{22} atoms

                 

     

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3 years ago
the potential at a point A is 30 V higher than at point B. How much work would you do moving 4.0 C charge from B to A?
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