K.E=1/2mv^2 K.E=1/2multiply1multiply8^2=32joules
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Answer:
Power input, P = 2880 watts
Explanation:
It is given that,
Voltage of the motor, V = 240 V
Current required, I = 12 A
Weight lifted, W = 2000 lb
It is lifting at a speed of 25 ft/min. We need to find the power input to the motor. The product of current and voltage is called power input of the motor.


P = 2880 watts
So, the power input of the motor is 2880 watts. Hence, this is the required solution.
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