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coldgirl [10]
3 years ago
10

Applications of machine ​

Physics
1 answer:
ddd [48]3 years ago
8 0
Hes ur clothes ur andwer is 27374747488

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I need help please help
Gnoma [55]

Answer:

ITS THE TOESSSSSSS FOR ME

3 0
3 years ago
Show which of the following functional forms work or do not work as solutions to this differential equation (known as 'the wave
Akimi4 [234]

Answer:

E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Explanation:

The wave equation is

           d²y / dx² = 1 /v²  d²y / dt²

Where v is the speed of the wave

Let's review the solutions

In this case y = E

a) E = A sin Bt

 This cannot be a solution because the part in x is missing

      dE / dx = 0

b) E = A cos (Bt + c)

There is no solution missing the Part in x

         dE / dx = 0

c) E = A x² t²

The parts are fine, but this solution is not an oscillating wave, so it is not an acceptable solution of the wave equation

d) E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Both are very similar

Let's make the derivatives

       dE / dx = -A B sin (Bx + Ct + D)

      d²E / dx² = -A B² cos (Bx + Ct + D)

      dE / dt = - A C sin (Bx + Ct + D)

      d²E / dt² = -A C² cos (Bx + Ct + D)

We substitute in the wave equation

      -A B² cos (Bx + Ct + D) = 1 / v² (-A C² cos (Bx + Ct + D))

       B² = 1 / v² (C²)

       v² = (C / B)²

       v = C / B

We see that the two equations can be a solution to the wave equation, the last one is the slightly more general solution

8 0
3 years ago
A candy-filled piñata is hung from a tree for Elia's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Tonja
Klio2033 [76]

Answer: v = 0.6 m/s

Explanation: <u>Momentum</u> <u>Conservation</u> <u>Principle</u> states that for a collision between two objects in an isolated system, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision.

Momentum is calculated as Q = m.v

For the piñata problem:

Q_{i}=Q_{f}

m_{p}v_{p}_{i}+m_{s}v_{s}_{i}=m_{p}v_{p}_{f}+m_{s}v_{s}_{f}

Before the collision, the piñata is not moving, so v_{p}_{i}=0.

After the collision, the stick stops, so v_{s}_{f}=0.

Rearraging, we have:

m_{s}v_{s}_{i}=m_{p}v_{p}_{f}

v_{p}_{f}=\frac{m_{s}v_{s}_{i}}{m_{p}}

Substituting:

v_{p}_{f}=\frac{(0.54)(4.8)}{(4.4)}

v_{p}_{f}= 0.6

Immediately after being cracked by the stick, the piñata has a swing speed of 0.6 m/s.

3 0
3 years ago
Red Riding Hood sat down to rest and placed her 1.20-kg basket of goodies beside her. A wolf came along, spotted the basket, and
anygoal [31]

Answer:

  117.6°

Explanation:

The vertical component of a force directed at some angle α from the vertical is ...

  F·cos(α)

We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...

  Fw·cos(25°) + Fr·cos(α) = 0

  cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030

  α ≈ arccos(-0.464030) ≈ 117.6°

Red was pulling at an angle of about 117.6° from the vertical.

_____

<em>Additional comment</em>

That's about 27.6° below the horizontal.

3 0
3 years ago
The most common example of a(n) ____ switched network is the conventional telephone system.
fenix001 [56]
CIRCUIT Switched network has the conventional telephone system as the most common example.

Circuit switching<span> is a method of implementing a telecommunication network </span><span>in which two network nodes </span><span>establish a dedicated communications channel or circuit </span><span>through the network before the nodes may communicate. The circuit guarantees the full bandwidth of the channel and remains connected for the duration of the communication session by functioning as though the nodes were physically connected like an electrical circuit.</span>

In a conventional telephone system, when a call is made from one telephone to another, switches within the the telephone exchanges create a continuous wire circuit between the two units for as long as the call lasts.
4 0
4 years ago
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