The elements helium, neon, and xenon are all part of the same ______ on a periodic table.

Chemistry

2 answers:

OLga [1]2 years ago

5 0

I think the answer would be b

egoroff_w [7]2 years ago

4 0

The answer to your guestion is B The elements helium, neon, xenon are in the same GROUP on a periodic table.

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Whitch statement is the best example of pseudosicience

Mars2501 [29]

Please include the statements

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3 years ago

Explain how to draw the electron-dot diagram for oxygen.

AlexFokin [52]

The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.

<h3>What is the electron dot diagram?</h3>

The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.

The electron dot diagram for the oxygen atom is drawn as follows:

The number of valence electrons in oxygen atom is determined; valence electrons = 6
The symbol for the oxygen atom is written
The valence electrons are shown as dots around the symbol of the element.

In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.

Learn more about electron dot diagram at: brainly.com/question/5835591

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1 year ago

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What i

g100num [7]

It's simple, just follow my steps.

1º - in 1 L we have $0.0100~g$ of $BaCO_3$

2º - let's find the number of moles.

$\eta=\frac{m}{MM}$

$\eta=\frac{0.0100}{197.3}$

$\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}$

3º - The concentration will be

$C=5.07\times10^{-5}~mol/L$

But we have this reaction

$BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}$

This concentration will be the concentration of $Ba^{2+}~~and~~CO_3^{2-}$

$K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}$

considering $[BaCO_3]=1~mol/L$

$K_{sp}=[Ba^{2+}][CO_3^{2-}]$

and

$[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L$

We can replace it

$K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})$

$K_{sp}\approx25.70\times10^{-10}$

Therefore the $K_{sp}$ is:

$\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}$

4 0

3 years ago

Read 2 more answers

When rolling a number cube 500 times, how many times you expect to get a 3?

andreyandreev [35.5K]

Answer:

$\frac{250}{3}$