The first thing you need to do with problem of this kind is to write the chemical equation. This would help you in calculations later. First, convert how many moles are there in 1.75g of carbon dioxide. Then, from the chemical equation you will know how many moles of sodium bicarbonate formed with 1 mole of carbon dioxide. Then convert the moles of sodium bicarbonate to grams using the molecular weight of the compound. You now have your answer.
Answer: CO is a limiting reagent with regards to the Fe production.
Explanation:
Moles of CO = 
moles of 
According to reaction , 3 mole of CO reacts with 1 mole of 
then , 0.4714 moles of CO will react with : 
moles of that is 0.1571 moles.
0.4714 moles of CO will react with 0.1571 moles of which means that CO is present in limited amount acting as limiting reagent.
Mole remaining of = 0.2673 mol - 0.1571 mol = 0.1102 mol
Hence, CO is a limiting reagent and is an excessive reagent.
Answer:
potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol
to get 1000 ml
Molar concentration = Mass concentration/Molar Mass
mass concentration = molar concentration x molar mass
mass concentration=0.1 M,
molar mass= 204.233 g/mol
so to get 1L
mass conc = 204.233 x 0.1
= 20.4233g for 1L or 1000 ml
to get 6.00 ml
if 20.4233g is for 1000ml
then to 6.00 ml
= 20.4233 x 6 / 1000
= 0.123g for 6.00 ml
according to the equation below
NaOH(aq) + KHC8H4O4(aq) --> KNaC8H4O4(aq) + H2O(l)
number of moles of NaOH is equal to that of KHP
so the same amount will be needed too, which is
= 0.123g
