H. using a pulley system can reduce the load force, over a greater distance.<span />
Answer:
d = 0.93 g/cm³
Explanation:
Given data:
Mass of object = 28 g
Volume of object = 3cm×2cm×5cm
density of object = ?
Solution:
Volume of object = 3cm × 2cm ×5cm
Volume of object = 30 cm³
Density of object:
d = m/v
by putting values,
d = 28 g/ 30 cm³
d = 0.93 g/cm³
Answer:
45.02 L.
Explanation:
- Firstly, we need to calculate the no. of moles of water vapor.
- n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol.
- We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.
<em><u>Using cross multiplication:</u></em>
1.0 mole of CO occupies → 22.4 L.
2.01 mole of CO occupies → ??? L.
∴ The volume of water vapor in 36.21 g = (22.4 L)(2.01 mole) / (1.0 mole) = 45.02 L.
Answer:
See the answer below
Explanation:
<em>The correct answer would be that the solute particles lower the solvent's vapor pressure, thus requiring a higher temperature to cause boiling.</em>
Dissolving a solute particle in a solvent leads to a decrease in the vapor pressure of the solvent above the resulting solution when compared to the pure solvent. The lower the vapor pressure of a liquid, the higher the temperature required for the liquid to boil and vice versa. Hence, a higher temperature would be needed to boil a solvent with dissolved solutes.
