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3 years ago

Identify the neutralization reaction.

Chemistry

1 answer:

olchik [2.2K]3 years ago

3 0

Answer:

3Ba(OH)₂ + 2H₃PO₄ → Ba₃(PO₄)₂ + 6H₂O

Explanation:

Neutralization reaction:

When an acid and base react they form water and salt.The reaction is called neutralization reaction.

General equation:

HX + BOH → BX + H₂O

From given reaction equations only option C is correct because only this reaction gives salt and water.

Chemical equation:

3Ba(OH)₂ + 2H₃PO₄ → Ba₃(PO₄)₂ + 6H₂O

Barium hydroxide is acting as a base. H₃PO₄ is an acid. Both these reactants react to form salt which is barium phosphate and water.

Other options are incorrect because non of these reaction produced salt and water. So option A is correct.

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Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

First we have to calculate the mass of $HCO_3^-$ in tablet.

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Now we have to calculate the moles of $HCO_3^-$ .

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$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

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