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coldgirl [10]
3 years ago
8

Generally, does the size of a radioactive sample affect half-life?

Chemistry
2 answers:
lions [1.4K]3 years ago
8 0
The quantity of radioactive nuclei at any given time will decrease to half as much in one half-life.

It is impossible to predict when an individual radioactive atom will decay
Natasha2012 [34]3 years ago
4 0

Answer:

The quantity of radioactive nuclei at any given time will decrease to half as much in one half-life.

Explanation:

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Gerald's science teacher mixed liquid X and liquid Y, both at room-temperature, in a large beaker. two beakers of clear solution
Pachacha [2.7K]

Answer:

the answer is C

Explanation:

7 0
3 years ago
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A solution of H 2 SO 4 ( aq ) H2SO4(aq) with a molal concentration of 8.01 m 8.01 m has a density of 1.354 g / mL . 1.354 g/mL.
anzhelika [568]

Answer:

[H₂SO₄] = 6.07 M

Explanation:

Analyse the data given

8.01 m → 8.01 moles of solute in 1kg of solvent.

1.354 g/mL → Solution density

We convert the moles of solute to mass → 8.01 mol . 98g /1mol = 785.4 g

Mass of solvent = 1kg = 1000 g

Mass of solution = 1000g + 785.4 g = 1785.4 g

We apply density to determine the volume of solution

Density = Mass / volume → Volume = mass / density

1785.4 g / 1.354 g/mL = 1318.6 mL

We need this volume in L, in order to reach molarity:

1318.6 mL . 1L / 1000mL = 1.3186 L ≅ 1.32L

Molarity (mol/L) → 8.01 mol / 1.32L = 6.07M

4 0
3 years ago
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Which of the following is a physical change?
Wewaii [24]

Answer:

O ice melts at 0°C that is the answer

5 0
3 years ago
Which statement best describes what makes a base weak?
dimulka [17.4K]

A base is weak when only a little of it dissolved in Water.

It images help u...

6 0
3 years ago
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A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of
mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.125

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.125=e^{-0.00440\times t}

t = 473 year

8 0
3 years ago
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