Answer:
M of HI = 5.4 M.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
<em>(XMV) acid = (XMV) base.</em>
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HI = (XMV) Ca(OH)₂.</em>
For HI; X = 1, M = ??? M, V = 25.0 mL.
For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.
<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>
I think the answer is B. static charge. I hope this helps! :)
Methyl chloride
dichloromethane
Answer:
1033.36g
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.
1 mole SO2 = 32 + (16x2) = 64g.
Now, If 64g of SO2 contains 6.02x10^23 molecules,
Therefore, Xg of SO2 will contain 9.72x10^24 i.e
Xg of SO2 = (64x9.72x10^24)/6.02x10^23
Xg of SO3 = 1033.36g.
Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules
The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs
<h3>what do you mean by half-life?</h3>
A substance's half-life is the amount of time it takes for half of it to decompose.
<h3>What is a half-life example?</h3>
Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.
When n half-lives have passed, the formula for estimating the amount still left is:-
A=A°/2^n
where,
A=initial amount
A°=remaining amount
n=t/t_{1/2}
A=150/2^t/30yrs
Learn more about half-life here:-
brainly.com/question/28001741
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