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denis-greek [22]
3 years ago
15

To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 400-loop-per

-meter circular coil 0.660 m in radius to create a 1.20-T field (typical of an MRI instrument) at its center with no iron present. The magnetic field of a proton is approximately like that of a circular current loop 0.650×10−15 m in radius carrying 1.05×104 A . What is the field at the center of such a loop?
Physics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

B = 4.059 x 10¹⁵ T

Explanation:

Given,

Number of loop, N = 400

radius of loop, r = 0.65 x 10⁻¹⁵ m

Current, I = 1.05 x 10⁴ A

Magnetic field at the center of the loop

B = \dfrac{\mu_0NI}{2R}

B = \dfrac{4\pi\times 10^{-7}\times 400 \times 1.05 \times 10^4}{2\times 0.65\times 10^{-15}}

B = 4.059 x 10¹⁵ T

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Which of these phase changes requires energy?
frutty [35]

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2 years ago
A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î
Allisa [31]

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Velocity v= (3i-5j+k) m/s

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We need to calculate the value \vec{v}\times\vec{B}

(\vec{v}\times\vec{B})=3i+4j+11k

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

\vec{F}=q(\vec{v}\times\vec{B})

Put the value into the formula

\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)

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|F|=2.6\times10^{-9}\ N

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