All categories

4 years ago

How much greater is the pressure at the deepest part of the ocean compared to that found at sea level?

2 answers:

6 0

The deepest part of the ocean is the Marianas Trench, where the water pressure is 1,000 times that of which is found at sea level.

Dima020 [189]4 years ago

6 0

C 1,000 times is the correct answer i think

You might be interested in

How many atoms of hydrogen exist in Na + H2O → NaOH + H2

Kazeer [188]

If you're talking about in an actual sample, you'd need more data like how many moles you have of the reactant or product.

Just in terms of the equation : there are two from the water in the reactant (left) side, and one from the sodium hydroxide and two for the hydrogen gas on the product (right) side, so 2+1+2=5 atoms of hydrogen.

8 0

4 years ago

PLEASE HELP! 25 POINTS!!!! I got the #1, just not #2 and #3. An industrial chemical company has opened a new plant that will pro

podryga [215]

Answer :

Part 1 : Balanced reaction, $3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

Part 2 : The theoretical yield of $NH_3$ gas = 440.96 g

Part 3 : The % yield of ammonia is 90.03 %

Solution : Given,

Mass of $N_2$ = 475 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $NH_3$ = 17 g/mole

Experimental yield of $NH_3$ = 397 g

Answer for Part (1) :

The balanced chemical reaction is,

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

Answer for Part (2) :

First we have to calculate the moles of $N_2$ .

$\text{Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molecular mass of }N_2}=\frac{475g}{28g/mole}=16.96moles$

From the given reaction, we conclude that

1 moles of $N_2$ gas react to give 2 moles of $NH_3$ gas

16.96 moles of $N_2$ gas react to give $\frac{2}{1}\times 16.96=33.92$ moles of $NH_3$ gas

Now we have to calculate the mass of $NH_3$ gas.

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(33.92moles)\times (17g/mole)=440.96g$

Therefore, the theoretical yield of $NH_3$ gas = 440.96 g

Answer for Part (3) :

Formula used for percent yield :

$\% \text{ yield of }NH_3=\frac{\text{ Experimental yield of }NH_3}{\text{ Theoretical yield of }NH_3}\times 100$

$\% \text{ yield of }NH_3=\frac{397g}{440.96g}\times 100=90.03\%$

Therefore, the % yield of ammonia is 90.03 %

3 0

3 years ago

2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) (balanced)

Triss [41]

Answer:

Percent yield = 65.2 %

Explanation:

The reaction determines this:

2 moles of Al react to 3 moles of chlorine gas in order to produce 2 mol of aluminum chloride.

We determine the moles of chlorine:

52 g . 1mol /70.9g = 0.733 moles of Cl₂

3 moles of gas can produce 2 moles of salt

Then, our 0.733 moles may produce (0.733 . 2) / 3 = 0.489 moles of AlCl₃

We convert moles to mass to predict the 100 % yield

0.489 mol . 133.3 g /mol = 65.19 g

Percent yield = (Yield produced / 100 % yield) . 100

Percent yield = (42.5 g / 65.19g) . 100 = 65.2 %

3 0

3 years ago

Which transition could represent an atom that emits a photon with 10.2 eVeV of energy?

AlekseyPX

There is a co2 contotution

7 0

2 years ago

The long-term weather patterns that are typical in a location are the location's___?

fenix001 [56]

Climate is an area's long-term weather patterns

3 0

3 years ago