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Lina20 [59]
3 years ago
8

How much greater is the pressure at the deepest part of the ocean compared to that found at sea level?

Chemistry
2 answers:
Leno4ka [110]3 years ago
6 0
The deepest part of the ocean is the Marianas Trench, where the water pressure is 1,000 times that of which is found at sea level.
Dima020 [189]3 years ago
6 0

C 1,000 times is the correct answer i think

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You hold two magnets together, end to end, and then let go. If the magnets stay together, the magnets are being _____.
Aleksandr-060686 [28]

Answer:

C-attracted.

Explanation:

When two magnets stay together they are being attracted. If they are pushing each other away, they are being repelled.

5 0
3 years ago
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26.8 moles of argon contain how many atoms?
Maru [420]
<span>1.61 × 1023 Multiply by 26.8 to get the answer.161.33 x 10 ^23   </span>
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3 years ago
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What are the units of k in the following rate law?
Ludmilka [50]

Answer:

B. \frac{1}{M^{2} s }

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * M^{2} * M^{1}

k= (M/s) / (M^{3})

k= \frac{1}{M^{2} s }

You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= \frac{M^{1-n} }{s }

k= \frac{M^{1-3} }{s }= \frac{m^{-2}}{s}= \frac{1}{M^{2} s }

8 0
4 years ago
Why are the oxidation and reduction half-reactions separated in an<br> electrochemical cell?
Mrac [35]

Answer:

The half-cells separate the oxidation half-reaction from the reduction half-reaction and make it possible for current to flow through an external wire.

Explanation:

7 0
3 years ago
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A certain chemical reaction releases 31.0 kj/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Aleksandr-060686 [28]

Answer:

See explanation.

Explanation:

Hello!

In this case, since we know the heat of reaction per gram of reactant and we should know the total energy of reaction, but it is not there, we are going to assume it is 1200 J as usual in these problems, so you can change it to whatever your given heat is.

In such a way, we set up the math as shown below:

m= 1200J*\frac{1kJ}{1000J}*\frac{1g}{31.0kJ}

Which results:

m=0.0387g

Best regards!

7 0
3 years ago
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