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vitfil [10]
3 years ago
6

10.1 and 10.5 witch one is greater

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
6 0

Answer:

10.5 is greater than 10.1

Step-by-step explanation:

.5 is greater than .1

OLga [1]3 years ago
3 0

Answer:

10.5

Step-by-step explanation:

Because the digit at tenths place in 10.5 is greater than that of in 10.1

5 > 1

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Write an equation of the line that has a slope of -5 and a y intercept of 4 in slope intercept form.
Fiesta28 [93]

Answer:

y = -5x + 4

Step-by-step explanation:

y=Mx+b

8 0
3 years ago
16,80, 400,...<br> Find the 6th term.
jekas [21]

Answer:

Step-by-step explanation:

50,000

I think

5 0
2 years ago
Still don’t get it idk lol
KonstantinChe [14]

Answer:

XQ = 12

Step-by-step explanation:

In this question it asks for XQ instead of x, but you need to find x first.

1. Find x.

XQ is half of MQ so this statement is true: 3x - 3 = 2(2x - 6)

Solve for x.

3x - 3 = 2(2x - 6)

Distribute 2.

3x - 3 = 4x - 12

Isolate x.

3x = 4x - 9

-x = -9

Divide -1 out.

x = 9

Now solve for XQ, which the equation is given.

XQ = 2(9) - 6

XQ = 18 - 6

XQ = 12

6 0
3 years ago
Read 2 more answers
What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15
Aneli [31]
First of all we have to arrange the data in ascending order as shown below:

28, 40, 43, 43, 45, 50, 50

Total number of values = 7

Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:

1st Half = 28, 40, 43
2nd Half = 45, 50, 50

Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.

IQR or the Inter Quartile Range is the difference of Q3 and Q1.

So, IQR= Q3 – Q1 = 50 – 40 = 10

Thus, IQR for the given data is 10
4 0
3 years ago
Read 2 more answers
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had
Stolb23 [73]

Answer:

Q1 z(s) is in the rejection region for H₀ ; we reject H₀. We can´t support the that means have no difference

Q2  CI 95 %  =  (  0,056 ;  0,164 )

Step-by-step explanation:

Sample information for people under 18

n₁  =  500

x₁ =  180

p₁  =  180/ 500    p₁  =  0,36    then  q₁  =  1 -  p₁     q₁ =  0,64

Sample information for people over 18

n₂  =  600

x₂  =  150

p₂  =  150 / 600   p₂ =  0,25   then   q₂  =  1 - p₂   q₂ =  1 - 0,25   q₂ = 0,75

Hypothesis Test

Null hypothesis                        H₀              p₁  =  p₂

Alternative Hypothesis           Hₐ              p₁  ≠  p₂

The alternative hypothesis indicates that the test is a two-tail test.

We will use the approximation to normal distribution of the binomial distribution according to the sizes of both samples.

Testin at CI =  95 %    significance level is  α = 5 %   α  =  0,05  and

α/ 2  =  0,025   z (c) for that α  is from z-table:

z(c) = 1,96

To calculate   z(s)

z(s)  =  ( p₁  -   p₂ ) / EED

EED = √(p₁*q₁)n₁  +  (p₂*q₂)/n₂

EED = √( 0,36*0.64)/500  +  (0,25*0,75)/600

EED = √0,00046  +  0,0003125

EED = 0,028

( p₁  -  p₂  )  =  0,36  -  0,25  = 0,11

Then

z(s)  =  0,11 / 0,028

z(s) = 3,93

Comparing  z(s) and  z (c)    z(s) > z(c)

z(s) is in the rejection region for H₀ ; we reject H₀. We can´t support the idea of equals means

Q2  CI  95 %   =  (  p₁  -  p₂  ) ±  z(c) * EED

CI 95%  =  ( 0,11   ±  1,96 * 0,028 )

CI 95%  = (  0,11  ±  0,054 )

CI 95 %  =  (  0,056 ;  0,164 )

8 0
3 years ago
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