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3 years ago

The formation of a standing wave requires _____.

Physics

2 answers:

erica [24]3 years ago

4 0

the formation of a standing wave requires interferencethe incoming and reflected waves of the same frequency

Colt1911 [192]3 years ago

3 0

Answer: The correct answer is "interference between the incoming and reflected waves of the same frequency"

Explanation:

Standing wave: Standing wave will form when two waves of equal frequency travelling in an opposite direction in the same medium. There is interference between the incoming and reflected waves of the same frequency.

These waves do not appear to move. There is an oscillation up and down in same phase. Standing wave consists of node and antinode.

Anti node: It is the location in the wave where the amplitude is minimum.

Node: It is the location in the wave where the amplitude is maximum.

Therefore, the correct option is "interference between the incoming and reflected waves of the same frequency ".

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Which statement accurately describes something that Yolanda can do as a part of her study?

Vikki [24]

Thank you for posting your question here at brainly. Below is Yoland's study:

<span>Yolanda is studying two waves. The first wave has an amplitude of 2 m, and the second has an amplitude of 3 m.
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I think the answer is "She can use constructive interference to generate a wave with an amplitude of 1.5 m."

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2 years ago

Read 2 more answers

A physics book slides off a table at 1.25ms and hits the ground after 0.4s

tresset_1 [31]

Answer:

Whats the question here?

7 0

2 years ago

A certain AM radio wave has a frequency of 1.12 x 100 Hz. Given that radio waves travel at

riadik2000 [5.3K]

Answer: 267 m

Explanation:

2.99x10^8 m/s

———————-

1.12 x 10^6 Hz

3 0

2 years ago

In example 18. 4 of the text, the deflection angle of the laser beam as it exits the prism is 22. 6º. If the prism had been made

Marrrta [24]

The deflection angle is 37.29º if the prism was made of polystyrene plastic.

What is a laser beam?

Laser beam is a light beam propagating dominantly in one direction.

It is a beam of radiation produced from a laser.

Here given that,

refraction index of glass, n1= 1.52

refraction index of polystyrene plastic, n2 = 1.59

deflection angle, B = 22.6º

For the second surface,

B = 45º - 22.6º

B = 22.40º

Now from the formula of Snell's law:

n1 sinФ = n2 sin B

sin B / sinФ = n1 / n2

sinФ = (sin 22.40º) * ( 1/ 1.59)

Ф = 37.29º

Hence,

The deflection angle is 37.29º if the prism was made of polystyrene plastic.

Learn more about laser beam here:

<u>brainly.com/question/4218151</u>

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3 0

1 year ago

Jack (mass 59.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. He collides with Jill (mass 47.0 k

Phantasy [73]

Answer:

Part(A): The magnitude of Jill's final velocity is $\bf{6.59~m/s}$ .

Part(B): The direction is $\bf{42.7^{0}}$ south to east.

Explanation:

Given:

Mass of Jack, $m_{1} = 59.0~Kg$

Mass of Jill, $m_{2} = 47..0~Kg$

Initial velocity of Jack, $v_{1i} = 8.00~m/s$

Initial velocity of Jill, $v_{2i} = 0$

Final velocity of Jack, $v_{1f} 5.00~m/s$

The final angle made by Jack after collision, $\alpha = 34.0^{0}$

Consider that the final velocity of Jill be $v_{2f}$ and it makes an angle of $\beta$ with respect to east, as shown in the figure.

Conservation of momentum of the system along east direction is given by

$~~~~&& m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f} \cos \alpha + m_{2}v_{2f}^{x}\\&or,& v_{2f}^{x} = \dfrac{m_{1}(v_{1i} - v_{1f} \cos \alpha)}{m_{2}}$

where, $v_{2f}^{x}$ is the component of Jill's final velocity along east. The direction of this component will be along east.

Substituting the value, we have

$v_{2f}^{x} &=& \dfrac{(59.0~Kg)(8.00~m/s - 5.00 \cos 34.0^{0}~m/s)}{47.0~Kg}\\~~~~~&=& 4.84~m/s$

Conservation of momentum of the system along north direction is given by

$~~~~&& v_{2f}^{y} + v_{1f} \sin \alpha = 0\\&or,& v_{2f}^{y} = - v_{1f} \sin \alpha = (8.00~m/s) \sin 34^{0} = 4.47~m/s$

where, $v_{2f}^{y}$ is the component of Jill's final velocity along north. The direction of this component will be along the opposite to north.

Part(A):

The magnitude of the final velocity of Jill is given by

$v_{2f} &=& \sqrt{(v_{2f}^{x})^{2} + (v_{2f}^{y})^{2}}\\~~~~~&=& 6.59~m/s$

Part(B):

The direction is given by

$\beta &=& \tan^{-1}(\dfrac{4.47~m/s}{4.84~m/s})\\~~~~&=& 42.7^{0}$

4 0

3 years ago