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Evgesh-ka [11]
4 years ago
4

Air is compressed slowly in a piston-cylinder assembly from an initial state where p1 = 1.4 bar, V1 = 4.25 m3 , to a final state

where p2 = 6.8 bar. During the process, the relation between pressure and volume follows pV = constant. For the air as the closed system, determine the work, in Btu.

Engineering
1 answer:
Ahat [919]4 years ago
8 0

Answer:

attached below

Explanation:

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A 900 kg car is accelerated from a speed of 10 m/s to 30 m/s. An estimated heat loss of 20 BTU's occurs during the acceleration.
Strike441 [17]

Answer:

Work = 651,1011 kJ

Explanation:

Let´s take the car as a system in order to apply the first law of thermodynamics as follows:

E_{in}- E_{out}=E_{system,final}- E_{system,initial}

Where

E_{in}- E_{out}=(Q_{in}-Q_{out})_{heat}+(W_{in}-W_{out})_{work}+(Em_{in}-Em_{out})_{mass}

And considering that there is no mass transfer and that the only energy flows that interact with the system are the heat losses and the work needed to move the car we have:

E_{in}- E_{out}=-Q_{out}+W_{in}

Regarding the energy system we have the following:

E_{system,final}- E_{system,initial}=(U_{f}-U_{i})_{internal}+(1/2m(V^2_{f}-V^2_{i}))_{kinetic}+(mg(h_{f}-h_{i}))_{potential}

By doing the calculations we have:

E_{system,final}- E_{system,initial}=[0,1*900]_{internal}+[0,5*900(30^2-10^2)/1000)_{kinetic}+(900*10*(20-0)/1000)_{potential}\\E_{system,final}- E_{system,initial}=90+360+180=630kJ

Consider that in the previous calculation, the kinetic and potential energy terms were divided by 1.000 to change the units from J to kJ.

Finally, the work needed to move the car under the required conditions is calculated as follows:

W_{in}=Q_{out}+E_{system,final}- E_{system,initial}\\W_{in}=21,1011+630=651,1011kJ

Consider that in the previous calculation, the heat loss was changed previously from BTU to kJ.

4 0
3 years ago
Often an attacker crafts e-mail attacks containing malware designed to take advantage of the curiosity or even greed of the reci
Mademuasel [1]

Answer:

1) The ethical act Amy should display is to open the Email since it came in through her personal inbox. However, further action should not be taken since ordinarily opening the mail will not disclose or corrupt her system either locally of her system on the server and web space.

2)  If such email came in, the first action i will take is to open the mail then take a pause to read through the instruction because most scam or malware comes with an array of further instructions.

After carefully reading through, i will call up Davey to confirm if he sent such mail which answer will obviously be a No and in the case where i am unable to get a call through to Davey, i will immediately delete the mail from my inbox to avoid the mistake of clicking any embedded link within the mail.

5 0
3 years ago
Describe how to mix and apply body filler?
malfutka [58]
This is all you need to mix body filler.
Start with a golf-ball size glob of filler.
Squeeze a ribbon of hardner across the filler.
Stir the mixture quickly, but do not "whip" it. ...
Mix until overall color is even.
Pick up an appropriate amount of filler for the task at hand.
8 0
3 years ago
A digital automatic level is used to profile a road centerline. The backsight reading is 3.57 ft on BM #1, which has an elevatio
liubo4ka [24]

Answer:

209.55 ft

Explanation:

Given Data:

Benchmark:

Reduced Level or Elevation = 210.50

Height of Instrument = Reduced Level + Back sight Reading

Height of Instrument = 210.50 + 3.57 = 214.07 ft

Turning Point:

Back sight Reading = 2.91 ft

Fore Sight Reading = 4.52

Reduced Level or Elevation of Turning Point = Height of Instrument – fore sight Reading

Reduced Level or Elevation of Turning Point = 214.07 – 4.52 = 209.55 ft

Height of Instrument at Turning Point = Reduced Level + Back sight Reading

Height of Instrument at Turning Point = 209.55 + 2.91 = 212.46 ft

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4 0
3 years ago
How a single force is resolved along the perpendicular axis acting an angle theta with horizontal?​
Nataly [62]

Answer:

A single force, which is acting at angle θ from a horizontal axis, can be resolved into components which act along the perpendicular axis.

Consider the perpendicular axis x and y, where x represents the horizontal axis and y represents vertical axis.

The Force is resolved into 2 parts, one acts along x-axis and is represent by X. The other acts along y-axis and is represented by Y.

From the diagram we can see that the Force and its components X and Y makes up a right angles triangle, where θ is the angle from the x-axis

<h3 /><h3>Find X:</h3>

We know that:

cosθ = Base/Hypotenuse

cosθ = X/F

X = Fcosθ

<h3>Find Y:</h3>

We know that:

sinθ = Perpendicular/Hypotenuse

sinθ = Y/F

Y = Fsinθ

<h3>Relation of Force and its Components:</h3>

Force F can be represent by:

F = Fcosθ (along x-axis) + Fsinθ (along y-axis)

As they form a right angled triangle, we can use Pythagoras Theorem to show the relation between Force and its components.

Hypotenuse² = Base² + Perpendicular²

F² = X² + Y²

F² = (Fcosθ)² + (Fsinθ)²

F = \sqrt{(F\cos\theta)^2+(Fsin\theta)^2}

Where θ can be found by using any of the trignometric functions.

6 0
3 years ago
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