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2 years ago

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A particle moving on a straight line has acceleration a = 5-3t, and its velocity is 7 at time t = 2. If s(t) is the distance fro

m, the origin, find s(2)-S(1).

1 answer:

Vikki [24]2 years ago

5 0

Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7

<h3>How to solve for the value of s2 - s1</h3>

We have

= $\frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt$

$= \int\limits^a_b {(5-3t)} \, dt$

$5t - \frac{3t^2}{2} +c$

v2 = 5x2 - 3x2 + c

= 10-6+c

= 4+c

$s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c$

S2 - S1

$=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)$

= 6 + 6+c - 2+3+c

12+c-5+c = 0

7 = c

Read more on acceleration here: brainly.com/question/605631

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3 years ago

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Answer:

The equation used to solve a diode is

$i_d = I_se^\frac{V_d}{V_T}-1$

$i_d$ is the current going through the diode
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$V_T$ is the voltage of the diode at a certain room temperature. by default, you always use $V_T=25.9mV$ for room temperature.

If you look at the equation, $i_d = I_se^\frac{V_d}{V_T}-1$ , you'd notice that the $e^\frac{V_d}{V_T}$ grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.

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$i_d\approx I_se^\frac{V_d}{V_T}$

Therefore, use $i_d= I_se^\frac{V_d}{V_T}$ to solve your equation.

Rearrange your equation to solve for $V_D$ .

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a.)

i.)

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<em>note: always use</em> $V_T=25.9mV$

ii.)

Just repeat part (i) but change to $I_s=-5\cdot10^{-12}A$

b.)

same process as part A. You do the rest of the problem by yourself.

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3 years ago

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Answer:

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$R$ - Radius of the rotor, measured in meters.

$L$ - Length of the rotor, measured in meters.

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$I = \frac{\pi}{16}\cdot \left(8960\,\frac{kg}{m^{3}} \right)\cdot (8.98\times 10^{-3}\,m)^{3}\cdot [3\cdot (8.98\times 10^{-3}\,m)^{2}+(25\times 10^{-3}\,m)^{2}]$

$I \approx 1.105\times 10^{-6}\,kg\cdot m^{2}$

The moment of inertia of the rotor is approximately $1.105\times 10^{-6}$ kilogram-square meters.

From D'Alembert's Formula we know that net force of rigid bodies experimenting rotation equals the product of moment of inertia and angular acceleration. In this case, the purpose is minimizing moment of inertia and it is done by modifying the shape of the cross section so that rotor could be aerodynamically more efficient.

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