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AlladinOne [14]
4 years ago
14

Enter a balanced chemical equation for the reaction between aluminum metal and liquid bromine.

Chemistry
1 answer:
Ludmilka [50]4 years ago
4 0

Answer:

  • 2Al (s) + 3Br₂ (l) → 2AlBr₃(s)

Explanation:

<u>1) Word equation:</u>

  • aluminum metal + liquid bromine → aluminum bromide

<u>2) Chemical equation:</u>

  • Al (s) + Br₂ (l) → AlBr₃(s)

<u>3) Balanced chemical equation:</u>

  • 2Al (s) + 3Br₂ (l) → 2AlBr₃(s)

<u>4) Notes:</u>

  • The most common oxidation state of aluminum is +3.

  • Bromine has 5 common oxidation states: -1, +1, +3, +5, and +7.

  • Since aluminum has a positive oxidation state, bromine must have the negative oxidation state, - 1.

  • In the molecular formula the valences (oxidation numbers) are exchanged as subscripts, that is the reason Al has subscript 1 (understood) while Br has subscript 3.

  • This is combination or synthesis reaction: two elements combine to form a new compound.

  • This is a very exothermic reaction which yields light (sparks) and heat.

  • The product, AlBr₃ is a molecular compound (not ionic).
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