How can the speed of a mechanical wave energy be calculated

Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete

Sonbull [250]

Answer:

work done in pumping the entire fuel is 466587 J

Explanation:

weight of the gasoline per volume = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 2 m

height of the tractor tank above the top of the tank = 5 m

work done in pumping fuel to this height = ?

First, we find the volume of the fuel

since the tank is cylindrical, we assume that the fuel within also takes the cylindrical shape.

Also, we assume that the fuel completely fills the tank.

volume of a cylinder = $\pi r^{2}l$

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x $1.5^{2}$ x 2 = 14.139 m^3

we then find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 14.139 = 93317.4 N

work done = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 93317.4 x 5 = 466587 J

8 0

3 years ago

The acceleration due to gravity vector is always in the ____ direction.

finlep [7]

It goes in the downward direction

4 0

3 years ago

The laws of reflection holds for__

RSB [31]

Answer:

c)both

Explanation:

The laws of reflection hold true for all the reflecting surfaces either spherical or plane. Therefore, the plane mirror, concave mirror and the convex mirror all will follow the laws of reflection.

5 0

3 years ago

Read 2 more answers

(a) Calculate the magnitude of the angular momentum of the earth in a circular orbit around the sun. Is it reasonable to model i

Anni [7]

Answer:

(a) $L=2.6742\times 10^{40}\, kg.m^2.s^{-1}$

(b) $L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}$

Explanation:

For Earth we have:

mass of earth, $m_E=5.97\times 10^{24}\, kg$

radius of earth, $R_E=6.38\times 10^6m$

orbital radius, $r=1.5 \times 10^{11}m$

period of rotation, $t_{rot}=24h=86400\, s$

period of revolution, $t_{rev}= 1 yr=3.156\times 10^7 s$

(a)

Angular momentum, $L=?$

∵ $L=I.\omega$ ...............................(1)

For a particle of mass m moving in a circular path at a distance r from the axis,

$I=m.r^2$

& $v=r.\omega$

Putting respecstive values in eq. (1)

$L=m_E\times r^{2}\times \omega$

$L=5.97\times 10^{24}\times (1.5 \times 10^{11})^2\times \frac{2\pi}{3.156\times 10^7}$

$L=2.6742\times 10^{40}\, kg.m^2.s^{-1}$

To model earth as a particle is reasonable because the distance between the sun and the earth is very large s compared to the radius if the earth.

(b)

For a uniform sphere of mass M and radius R and an axis through its center, $I=\frac{2}{5}M.R^2$

using eq. (1)

$L_s=(\frac{2}{5}m_E.R_E^2) \omega$

$L_s=\frac{2}{5} \times 5.97\times 10^{24} \times 6.38\times 10^6\times \frac{2\pi}{86400}$

$L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}$

6 0

3 years ago

What is the difference between a scalar and vector quantity? Give an example of each

Mkey [24]

Scalar quantity: one dimensional measurement of a quantity, like temperature, or mass. Vector: more than one number associated with it. Ex: Displacement, speed, velocity.

5 0

3 years ago