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torisob [31]
3 years ago
6

How can the speed of a mechanical wave energy be calculated

Physics
1 answer:
Slav-nsk [51]3 years ago
5 0
Speed = frequency * wavelength
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Why is respiration considered a chemical change?​
igor_vitrenko [27]

Answer:

In the oxidation of glucose, carbon dioxide and water are formed. As new products are formed of different composition and characteristics, the respiration is considered as a chemical change.

Explanation:

hope that works

5 0
3 years ago
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A wave has a frequency of 34 Hz and a wavelength of 2.0 m. What is the
Korolek [52]

Answer:

v=<u>FX</u>

<u>v=</u><u>3</u><u>4</u><u>(</u><u>2</u><u>.</u><u>0</u><u>)</u>

<u>v=</u><u>6</u><u>8</u><u>m</u><u>/</u><u>s</u>

8 0
3 years ago
I need some help with this problem.
dalvyx [7]

This picture is a graph.  Do you see the marks over on the left side ? 
It says "Brightness".  The Low brightness is on the bottom, and the
High brightness is on the top.  This shows you that the brightest stars
are the highest ones on the graph.

Now look on the graph.  Down near the bottom are Proxima Centauri and
the white dwarfs.  Also, our Sun is not too far up.  Way up near the top, you
see Supergiants.  "Betelgeuse" is on the right side, and "Spica" is on the
left side.  Those are the brightest ones on the graph.

The choices in your question are cut off below the bottom of thepicture.  But
this much discussion should be enough to help you choose the best answer.


3 0
3 years ago
Describe one elastic collisions and one inelastic collisions that you observed in your daily activities. In the inelastic collis
Serhud [2]

Answer:

A typical example of an elastic collision that can be observed is the collision of billiard balls, while an inelastic collision is presented in cars collisions.

Explanation:

In an inelastic collision, the energy system is lost in making the permanent deformation over car's structures due to the impact. As can be stated below, the final and initial kinetic energy are expressed:

[tex] Ei =0.5*m1.v1_{i}^2+m2.v2_{i}^2[/text]  

[tex] Ef =0.5*m1.v1_{f}^2+m2.v2_{f}^2[/text]  

Where the subscripts 1 and 2 relate to each car. In the final energy equation Ef, the car's final velocity will be lower than the respective initial velocities.

[tex] v1_{f}<v1_{i}[/text]  

[tex] v2_{f}<v2_{i}[/text]  

Take into account that car's masses still being the same after the collision, therefore the energy losses are always because of cars velocities changes:

[tex] Ef<Ei[/text]

In the elastic collision, there will be little or negligible deformations and that won't make energy losses. But this statement doesn't affirm that billiard balls velocities will be the same. In fact, could happen that one ball increases its velocities if the other ball decreases its velocity, but taking into account that the energy will always conserve.

[tex] v2_{f}>v2_{i}[/text] if [tex] v1_{f}<v1_{i}[/text]

or  

[tex] v1_{f}>v1_{i}[/text] if [tex] v2_{f}<v2_{i}[/text]

Under the assumption that balls masses still being the same:

[tex] Ef=Ei[/text]

3 0
3 years ago
Dewayne reviews Kepler’s laws by making the table shown. Which label belongs in each cell of the table?
Stels [109]

There are three laws which are postulated by Kepler for planetary motion.

Kepler's first law: As per the first law of Kepler,the orbits of planets around the sun is elliptical in nature in stead of circular. The sun is situated always at one of its foci.

Second law: Planets are moving in such a way that the areal velocity of the planets are constant i.e planets sweep out equal ares in equal interval of time.

Third law: The square of time period of planets around the sun is directly proportional to the cube of semi major axis.

       Mathematically\ T^{2} \alpha\ R^{3}

where T is the time period and R is semi major axis.

Hence the correct answer to the question is C i.e third,first,second.

6 0
3 years ago
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