What will the surface charge density be if the radius of the disk is doubled but its total charge remains the same
1 answer:
You might be interested in
Answer:
103239.89 days
Explanation:
Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
a³ / T² = 7.496 × 10⁻⁶ (a.u.³/days²)
where,
a is the distance of the semi-major axis in a.u
T is the orbit time in days
Converting the mean distance of the new planet to astronomical unit (a.u.)
1 a.u = 9.296 × 10⁷ miles
Substituting the values into Kepler's third law equation;
(days)²
T = 103239.89 days
An estimate time T for the new planet to travel around the sun in an orbit is 103239.89 days
To solve this problem we will apply the linear motion kinematic equations. On these equations we will define the speed as the distance traveled in a space of time, and that speed will be in charge of indicating the reaction rate of the individual. In turn, using the ratio of speed, position and acceleration, we will clear the position and determine the distance necessary for braking.
The relation to express the velocity in terms of position for constant acceleration is as follows
Here,
u = Initial velocity
v= Final velocity
a = Acceleration
= Initial position
s = Final position
PART 1) Calculate the displacement within the reaction time
In this case we can calculate the shortest stopping distance
PART 2)
PART 1) Calculate the displacement within the reaction time
In this case we can calculate the shortest stopping distance
While a person without alcohol would cost 517ft to slow down, under alcoholic substances that distance would be 616ft