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BartSMP [9]
3 years ago
9

What will the surface charge density be if the radius of the disk is doubled but its total charge remains the same

Physics
1 answer:
zaharov [31]3 years ago
8 0

Answer:

the new surface charge density = Q/4πr²( initial surface charge density divided by 4)

Explanation:

charge density(surface) = Q/A = charge/area

let r be the initial radius of the disk

therefore, area A = πr²

charge density = Q/πr²

Now that the radius is doubled, let it be represented as R

∴ R = 2r

Recall, charge density = Q/A

A = πR = π(2r)² = 4πr²

the new surface charge density = Q/4πr²

the initial surface charge density divided by 4

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Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

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Bold are vectors; where L is the angular momentum, r the position of the particle and p its linear momentum

One of the easiest ways to make this vector product is with the use of determinants

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