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creativ13 [48]
4 years ago
11

Material through which a wave passes

Physics
1 answer:
EastWind [94]4 years ago
5 0
The material in which a wave travels through, such as a solid or a liquid, is known as a "medium." I hope this helps out!
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A rock is stuck deep in the dirt. When you pull on the rock to remove it, what type of force are you exerting?
aleksandrvk [35]
It is Tension as the other 3 answer choices would not make sense. Compression would mean you are pressing the rock on both sides or in this case, pushing it into the dirt. It can't be nuclear force as you are pulling out a rock. Air resistance would not make sense either as there is no air involved in the scenario at all.
4 0
4 years ago
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One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
svet-max [94.6K]

Given:

• Mass, m = 0.200 mg

,

• Speed, v = 3.00 x 10³ m/s

,

• Time, t = 6.00 x 10^⁻⁸ s.

Let's calculate the force exerted.

Using the inpulse-momentum theroerm, we have:

impulse = change in momemntum

Where:

Impulse = force x time

change in momentum = mass x velocity.

Thus, we have:

F\times6.00\times10^{-8}=(0.200\times10^{-6})\times(3.00\times10^3)

Let's solve for the force F:

\begin{gathered} F=\frac{(0.200\times10^{-6})(3.00\times10^3)}{6.00\times10^{-8}} \\  \\ F=10000N \end{gathered}

Therefore, the force exterted is 10000 N.

ANSWER:'

10000 N

4 0
1 year ago
Which is unnecessary to include when accurately drawing ray diagrams?
VashaNatasha [74]

Answer:

Focal length

Explanation: No need for one...

6 0
3 years ago
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An object completes one and half revolution of a circle of radius R calculate the displacement and distance
Papessa [141]

Answer:

Distance is path length covered by particle. When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. ... Hence displacement is equal to diameter or 2 times the radius of circle.

8 0
3 years ago
You are standing in a building whose height (40m) you throw a ball downward at a angle of -30 at a speed of (10m/s) acceleration
jeyben [28]

Answer: 3.41 s

Explanation:

Assuming the question is to find the time t the ball is in air, we can use the following equation:

y=y_{o}+V_{o}sin \theta t-\frac{1}{2}gt^{2}

Where:

y=0m is the final height of the ball

y_{o}=40 m is the initial height of the ball

V_{o}=10 m/s is the initial velocity of the ball

t is the time the ball is in air

g=9.8 m/s^{2} is the acceleration due to gravity  

\theta=30\°

Then:

0 m=40 m+(10 m/s)(sin(30\°))t-\frac{1}{2}9.8 m/s^{2}t^{2}

0 m=40 m+5m/s t-4.9 m/s^{2}t^{2}

Multiplying both sides of the equation by -1 and rearranging:

4.9 m/s^{2}t^{2}-5m/s t-40 m=0

At this point we have a quadratic equation of the form at^{2}+bt+c=0, which can be solved with the following formula:

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

Where:

a=4.9

b=-5

c=-40

Substituting the known values:

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(4.9)(-40)}}{2(4.9)}

Solving the equation and choosing the positive result we have:

t=3.41 s  This is the time the ball is in air

5 0
4 years ago
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