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3 years ago

Material through which a wave passes

Physics

1 answer:

EastWind [94]3 years ago

5 0

The material in which a wave travels through, such as a solid or a liquid, is known as a "medium." I hope this helps out!

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A wave with a large amplitude has a lot of a.vibration b.speed c.energy

adoni [48]

A wave with a large amplitude has a lot of a.vibration b.speed  c.energy

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3 years ago

Read 2 more answers

We can reasonably model a 90-W incandescent lightbulb as a sphere 7.0cm in diameter. Typically, only about 5% of the energy goes

Ronch [10]

Answer:

292.3254055 W/m²

469.26267 V/m

$1.56421\times 10^{-6}\ T$

Explanation:

P = Power of bulb = 90 W

d = Diameter of bulb = 7 cm

r = Radius = $\frac{d}{2}=\frac{7}{2}=3.5\ cm$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

The intensity is given by

$I=\frac{P}{A}\\\Rightarrow I=\frac{90}{4\pi 0.035^2}\\\Rightarrow I=5846.50811\ W/m^2$

5% of this energy goes to the visible light so the intensity is

$I=0.05\times 5846.50811\\\Rightarrow I=292.3254055\ W/m^2$

The visible light intensity at the surface of the bulb is 292.3254055 W/m²

Energy density of the wave is

$u=\frac{1}{2}\epsilon_0E^2$

Energy density is also given by

$\frac{I}{c}=\frac{1}{2}\epsilon_0E^2\\\Rightarrow E=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E=\sqrt{\frac{2\times 292.3254055}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E=469.26267\ V/m$

The amplitude of the electric field at this surface is 469.26267 V/m

Amplitude of a magnetic field is given by

$B=\frac{E}{c}\\\Rightarrow B=\frac{469.26267}{3\times 10^8}\\\Rightarrow B=1.56421\times 10^{-6}\ T$

The amplitude of the magnetic field at this surface is $1.56421\times 10^{-6}\ T$

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3 years ago

A light-emitting diode (LED) connected to a 3.0 V power supply emits 440 nm blue light. The current in the LED is 11 mA , and th

zimovet [89]

Answer:

3.73 * 10^16 photons/sec

Explanation:

power supply = 3.0 V

Emits 440 nm blue light

current in LED = 11 mA

efficiency of LED = 51%

Calculate the number of photons per second the LED will emit

first step : calculate the energy of the Photon

E = hc / λ

=( 6.62 * 10^-34 * 3 * 10^8 ) / 440 * 10^-9

= 0.0451 * 10^-17 J

Number of Photon =( power supply * efficiency * current ) / energy of photon

= ( 3 * 0.51 * 11 * 10^-3 ) / 0.0451 * 10^-17

= 3.73 * 10^16 photons/sec

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3 years ago

¿Piensas que algunos fenómenos meteorológicos pueden deberse a las relaciones que existen entre las variables de presión, volume

lakkis [162]

Sí, porque tanto las leyes de Gauss, boyle, etc, relacionan estos comportamientos con el comportamiento de los gases, los cuales son los que ocasionan los diferentes fenómenos naturales y meteorológicos.

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Calculate the displacement of a bee that flew out of the beehive due east for 4 km, went around a 0.52 m in diameter poplar tree

stiks02 [169]

Answer:

the only thing thats confusing me is no ?

Explanation:

please explain thank you :)

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