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tangare [24]
2 years ago
6

If you were standing at the center of curvature in front of a concave mirror, what image would be projected?

Physics
2 answers:
matrenka [14]2 years ago
6 0
"<span>The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are" is the type of image among the choices given in the question that would be projected. The correct option among all the options that are given in the question is the first option. I hope it helps you.</span>
Bas_tet [7]2 years ago
5 0

Answer:

The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

Explanation:

As we know that the object position is at center of curvature of the mirror

So here the distance is given as

d = R = 2f

now by mirror formula of relation between distance of image and distance of object

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

\frac{1}{d_i} + \frac{1}{2f} = \frac{1}{f}

d_i = 2f

so image will form at the position of object itself

Now we will say that the magnification of the object will be

M = -\frac{d_i}{d_o} = -1

so image will be upside down and same as that the height of object

so correct answer would be

The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

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Answer:

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

Explanation:

The photoelectric effect occurs when light is shined on metals such as zinc beyond a certain frequency (the threshold frequency), which causes electrons to escape from the zinc. The electrons which are fleeing are called photo electrons.

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Answer:

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Explanation:

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- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

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