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nikitadnepr [17]
4 years ago
11

If a wave has a period of 0.5 s, what is its frequency

Physics
1 answer:
Naddik [55]4 years ago
8 0
Frequency is 1/period.  f=1/0.5 = 2Hz
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A single sports fan is capable of yelling at an intensity level of 80 decibels from a given distance. If 10,000 similar fans wer
AleksandrR [38]

Answer:

The correct answer is part 'c' 160 dB

Explanation:

When noise levels of different intensities are superimposed the resultant intensity is given by the equation

L_{avg}=20log(\frac{1}{N}\sum_{i=1}^{N}(10^{\frac{L_{i}}{20}}))\\

where,

L_{i} is the intensity of a general sound level

Since we have 10000 fans each producing sound of 80dB thus the resultant intensity is given using the above formula as

L_{avg}=20log(\frac{1}{10000}\sum_{i=1}^{10000}(10^{\frac{80}{20}}))\\

\therefore L_{eq}=160dB

7 0
3 years ago
Who would benefit of your own handled problem?why?​
Bezzdna [24]
You would benefit from your own handled problem because you solved a problem you had.

i’m pretty sure that’s it, going off the info i had.
5 0
2 years ago
Read 2 more answers
A square coil, enclosing an area with sides 3.2 cm long, is wrapped with 2,720 turns of wire. A uniform magnetic field perpendic
marishachu [46]

Answer

\epsilon = -0.74\ V

Explanation:

given,                          

Side of square coil = 3.2 cm            

Number of turns = 2720                  

magnetic field in the coil increases to = 0.45 T

time interval = 1.7 s                  

average induced voltage in the coil = ?

length = 0.032 m                      

Area = 0.032² = 0.001024 m²

induced voltage                  

\epsilon = -NA \dfrac{dB}{dt}

\epsilon = -2720 \times 0.001024 \times \dfrac{0.45}{1.7}

\epsilon = -0.74\ V                          

The average voltage induced in the coil is equal to \epsilon = -0.74\ V                                              

3 0
3 years ago
This problem has been solved!
Liono4ka [1.6K]

Answer:

Explanation:

In this problem we can use Bohr's atomic model, to deal with the electronic transition, so we can have transitions between two given states.

           ΔE = E_{f} -E₀

Lower state     final state                     energy

Fundamental      first excited state          ΔE₁ = -2.4 - (-4.7)  = 2.3 eV

Fundamental      second excited state   ΔE₂ = -1.0 - (-4.7) = 3.7 eV

Fundamental      third excited state        ΔE₃ = -0.3 - (-4.7) = 4.4 eV

As they indicate that there are no electrons in the excited states these are the only possible transitions.

When a wide range of light strikes, the frequencies of these energies are absorbed and observed as black bands (absence of radiation) in the spectrum.

3 0
3 years ago
What is the formula s = dt used to calculate?
andriy [413]
Speed equals distance times time
5 0
4 years ago
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